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Sphinxa [80]
3 years ago
12

Find the distance between the two points rounding to the nearest tenth (if necessary).

Mathematics
1 answer:
hichkok12 [17]3 years ago
6 0

Answer:

√90

Step-by-step explanation:

d=√((x2-x1)²+(y2-y1)²)

=√(-1-8)²+(5-2)²

=√(-9)²+(3)²

=√(81)+(9)

=√90

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Evelyn's made a cake in the shape of a circus tent the cake consisted of a cylinder and a cone .The height of the cone is half t
Lera25 [3.4K]
The volume of the cake is 1470 in³. 
volume of a cylinder = πr² x height
(Think about how a cylinder is basically a bunch of circles stacked on top of each other. To find the volume, first you need the area of the circle (πr², then you multiply by how many circles you are stacking on top of each other (height)) 

we know the diameter of the cylinder is 12 in. and the radius is half of the diameter. 
half of 12 is 6, therefore the radius is 6 in. or r = 6 
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1470 = (3.14)(6²)(height)
1470 = 3.14 x 36 x height
1470 = 113.04 x height
height ≈ 13 in

Now that we know the height of the cylinder is about 13 in., we know the height of the cone, because the problem says that the height of the cone is half the height of the cylinder. 
half of 13 is 6.5, therefore the height of the cone is 6.5 
the radius of the cone is the same as that of the cylinder, 6 in. 

volume of a cone = πr² × (height ÷ 3)

volume of the cone = (3.14)(6²)(6.5 ÷ 3)
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Now all that's left to find the volume of the whole cake is to add the volume of the cylinder to the volume of the cone. 

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6 0
4 years ago
The coordinate grid shows a pentagon. The pentagon is translated 4 units to the left and 9 units down to create a new pentagon.
Harrizon [31]
(X-4, y-9) since it moves left its negative and the y went down makes that negative too
7 0
3 years ago
Z=a/b+c/d solve for A
PilotLPTM [1.2K]

Answer: a=\frac{b(zd-c)}{d}

Step-by-step explanation:

Having the following equation given in the exercise:

z=\frac{a}{b}+\frac{c}{d}

You can solve for "a" following this procedure:

1. You can apply the Subtraction property of equality and subtract \frac{c}{d} from both sides of the equation:

z-(\frac{c}{d})=\frac{a}{b}+\frac{c}{d}-(\frac{c}{d})\\\\z-\frac{c}{d}=\frac{a}{b}

2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:

\frac{zd-c}{d}=\frac{a}{b}

3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:

(b)(\frac{zd-c}{d})=(\frac{a}{b})(b)\\\\a=\frac{b(zd-c)}{d}

6 0
3 years ago
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