Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
Answer:
Step-by-step explanation:
we know that
----> by supplementary angles (form a linear pair)
Solve for x
Combine like terms
subtract 99 both sides
Divide by 3 both sides
7(10 visits) ≤ 68
70 ≤ 68
Not Viable
7(9 visits) ≤ 68
63 ≤ 68
Viable
The first solution is not viable because 10 visits will give a total cost of $70 per month, which is $2 over his monthly budget of $68.
The second solution is viable. He could visit the gym a maximum of 9 times per month for a total of $63 a month and that will be under his $68 monthly budget.
Hope this helps! :)
