What I can make out is, check the picture, that'd be the dimensions of the room.
therefore, the surface area of that room is
2 10x25 rectangles, front and back
2 30x10 rectangles, left and right
and 2 25x30 rectangles, top and bottom
so the area will be (2*10*25) + (2*30*10) + (2*25*30), which gives us 2600 square feet though, not yards.
let's add the doors, windows and others which is 1275, so 2600 + 1275, that gives us 3875 square feet.
now, the paint is 9.5 for square yard, no feet, so let's do some conversion then,
![\bf \begin{array}{ll} yards&feet\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1yd&3ft\\ (1yd)^2&(3ft)^2\\ yd^2&3^2ft^2\\ &9ft^2 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bll%7D%0Ayards%26feet%5C%5C%0A%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%26%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%5C%5C%0A1yd%263ft%5C%5C%0A%281yd%29%5E2%26%283ft%29%5E2%5C%5C%0Ayd%5E2%263%5E2ft%5E2%5C%5C%0A%269ft%5E2%0A%5Cend%7Barray%7D)
so, if there are 9 square feet in one square yard, how many square yards are there in 3875 square feet?
![\bf \begin{array}{ccll} yd^2&ft^2\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1&9\\ x&3875 \end{array}\implies \cfrac{1}{x}=\cfrac{9}{3875}\implies \cfrac{3875}{9}=x](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%0Ayd%5E2%26ft%5E2%5C%5C%0A%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%26%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%5C%5C%0A1%269%5C%5C%0Ax%263875%0A%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B1%7D%7Bx%7D%3D%5Ccfrac%7B9%7D%7B3875%7D%5Cimplies%20%5Ccfrac%7B3875%7D%7B9%7D%3Dx)
that's how many yd² are there in 3875 ft².
now, we know for every yd², is $9.50, so then the cost will be