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Andre45 [30]
3 years ago
8

If f(x) = 52, what is the value of f(-6), to the nearest hundredth (if necessary)?

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer:

the correct answer is 52

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Find the area of a circle circumscribed about an equilateral triangle whose side is 18 inches long. 81 108 243
jekas [21]

Answer:

Area=339.2920in^2 \ or \ 108\pi \ in^2

Step-by-step explanation:

Area of circle is given as:

A=\pi\ r^2

Where r=radius

To find radius of a circle circumscribing an equilateral triangle, we use the expression

r=\frac{a\sqrt3}{3}

Where, a is the length of sides of the equilateral triangle. Therefore:-r=\frac{18\sqrt3}{3}\\r=6\sqrt3 \ or \ 10.3923in

We can then proceed and calculate the area of the circle as follows:-

A=\pi\ r^2\\A=\pi(10.3923)^{2}\\A=339.29\ or \ 108\pi

*The attached picture illustrates what the circumscribed equilateral triangle looks like

4 0
4 years ago
Tino works at a retail clothing store as a sales clerk and part of his paycheck is based on commission, meaning that it is deter
Elena-2011 [213]

Answer:

$206,7

Step-by-step explanation:

6 0
3 years ago
Find the value ,when 17 more than - 6​
myrzilka [38]

Answer: 11

Step-by-step explanation:

From the question, we are told to calculate the value when 17 is more than -6​. This question simply means that we should add -6 and 17 together. This would then be:

= -6 + 17

= 11

Therefore, the answer is 11.

4 0
3 years ago
In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.
ankoles [38]
<h2>Answer:</h2>

\boxed{\overline{MN}=37.96}

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find \overline{MN}. Since:

\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm

and \overline{MN} is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

\overline{RN}=\overline{QN}

By Pythagorean theorem, for triangle NQP:

\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}

Applying Pythagorean theorem again, but for triangle MQN:

\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}

3 0
3 years ago
Simplify 12 +3 [5+(4-2)]
horrorfan [7]
12 + 3 [5 + (4-2)] = 
12 + 3 [ 5 + 2 ] =
12 + 3 [ 7] =
12 + 21 =
33 <===
7 0
3 years ago
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