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ANTONII [103]
3 years ago
13

A girl has 8 coins in dimes and quarters. Their value is $1.55. How many quarters does she have?

Mathematics
2 answers:
liberstina [14]3 years ago
8 0
<span>A girl has 8 coins in dimes and quarters. Their value is $1.55. How many quarters does she have? 5 quarters

</span>
masha68 [24]3 years ago
4 0
How many quarters does she have? The girl has 3 Quarters all together.
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Phoenix [80]

Answer: Rs. 11,520

Step-by-step explanation:

As the method of compounding is not stated, the default of simple interest will be used.

Simple interest is a fixed amount that is paid over the course of the loan and is based on the original amount borrowed.

Formula is:

Amount owed = Amount borrowed * ( 1 + rate * time)

= 8,000 * ( 1 + 8% * 5.5 years)

= 8,000 * 1.44

= rs 11,520

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Mr. Simpson deposits his money in a savings account at the Springfield Bank. Would he earn more money with simple interest or wi
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THE ANSWER IS D

Step-by-step explanation:

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URGENT!!!! What is the distance from (−2, 4) to (0, −6)? Round your answer to the nearest hundredth. 9.23 units 10.20 units 10.9
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The distance between two points knowing theirs coordinates:

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\\ \bull\tt\longmapsto 5(x-2)\geqslant 4(x-2)

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Suppose the number of radios in a household has a binomial distribution with parameters n=11 and p=40%. Find the probability of
Ivenika [448]

Answer:

Step-by-step explanation:

The formula for binomial distribution is expressed as

P(x=r) = nCr × q^(n-r) × p^r

From the information given,

n = 11

p = 40% = 40/100 = 0.4

q = 1 - 0.4 = 0.6

x represent the number of radios

a) P( x = 1) or P(x = 9)

P(x = 1) = 11C1 × 0.6^(11-1) × 0.4^1

P(x = 1) = 0.027

P(x = 9) = 11C9 × 0.6^(11-9) × 0.4^9

P(x = 9) = 0.0052

P( x = 1) or P(x = 9) = 0.027 + 0.0052 = 0.0322

b) P(x lesser than or equal to 7) = P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6)

P(x = 0) = 11C0 × 0.6^(11-0) × 0.4^0 = 0.004

P(x = 1) = 0.027

P(x = 2) = 11C2 × 0.6^(11-2) × 0.4^2 = 0.089

P(x = 3) = 11C3 × 0.6^(11-3) × 0.4^3 = 0.177

P(x = 4) = 11C4 × 0.6^(11-4) × 0.4^4 = 0.24

P(x = 5) = 11C5 × 0.6^(11-5) × 0.4^5 = 0.22

P(x = 6) = 11C6 × 0.6^(11-6) × 0.4^6 = 0.15

P(x = 7) = 11C7 × 0.6^(11-7) × 0.4^7 = 0.15

P(x lesser than or equal to 7) = 0.004 + 0.027 + 0.089 + 0.177 + 0.24 + 0.22 + 0.15 + 0.07 = 0.977

c) P(x greater than or equal to 5) = 1 - P(x lesser than or equal to 4) = 1 - (0.004 + 0.027 + 0.089 + 0.177 + 0.24) = 1 - 0.537 = 0.463

d) P(x lesser than 9) = P(x lesser than or equal to 7) + P(x = 8)

P(x = 8) = 11C8 × 0.6^(11-8) × 0.4^8 = 0.02

P(x lesser than 9) = 0.977 + 0.02 = 0.997

e. P(x greater than 7) = 1 - P(x lesser than or equal to 7) = 1 - 0.977 = 0.023

5 0
3 years ago
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