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eduard
2 years ago
13

3. You have $20 to spend at the snack bar. All of the

Mathematics
2 answers:
IRINA_888 [86]2 years ago
8 0

Answer:

A) $17.50

B) $11.25

C) $5

Step-by-step

1.25 x the amount of snacks

Ket [755]2 years ago
3 0
A) $17.50
B) $11.25
C) $5
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OwOoWoOwO pls answer, sorry about the random burst im really bad at math
Nataly [62]

Answer:

0.46

Step-by-step explanation:

42.78/m = 93

=> m = 42.78/93

=> m = 0.46

Hope my answer helps :)

7 0
2 years ago
Read 2 more answers
Modern car company has come out with a new car model. Market analysts predict that 4,600 cars will be sold in the first month an
Arte-miy333 [17]

The first five terms of the sequence are; 4,600, 4,550, 4,500, 4,450, 4,400 and the total predicted number of sold cars for the first year is 51,900 cars

<h3>Arithmetic sequence</h3>

  • First month, a = 4,600 cars
  • Common difference, d = -50 cars

First five terms;

a = 4,600

a + d = 4600 + (-50)

= 4600 - 50

= 4,550

a + 2d

= 4600 + 2(-50)

= 4600 - 100

= 4,500

a + 3d

= 4,600 + 3(-50)

= 4,600 - 150

= 4,450

a + 4d

= 4600 + 4(-50)

= 4,600 - 200

= 4,400

cars predicted for the twelfth month.

a + 11d

= 4600 + 11(-50)

= 4600 + 550

= 4,050

Total predicted number of sold cars for the first year:

Sn = n/2{2a + (n - 1)d }

= 12/2{2×4600 + (12-1)-50}

= 6{9200 + 11(-50)}

= 6(9,200 - 550)

= 6(8,650)

= 51,900 cars

Learn more about arithmetic sequence:

brainly.com/question/6561461

#SPJ1

7 0
2 years ago
Please help in maths
Readme [11.4K]

The equivalent expressions of 22c + 33d are (a), (c) and (e)

<h3>How to determine the equivalent expressions?</h3>

The expression is given as:

22c + 33d

Factor out 11 from the expression

11(2c + 3d)

Multiply by 1

1 * 11(2c + 3d)

Express 1 as -1 * -1

-1 * -1 * 11(2c + 3d)

Evaluate the product

(-11) * (-2c - 3d)

Also, we have:

22c + 33d

Multiply by 1

(22c + 33d) * 1

Express 1 as 3/3

(22c + 33d) * 3/3

Evaluate the product

(66c + 99d) * 1/3

Hence, the equivalent expressions are (a), (c) and (e)

Read more about equivalent expressions at:

brainly.com/question/27911936

#SPJ1

7 0
1 year ago
How was your day?<br> (just answer something random for points)
Korolek [52]

it was fine, thanks for asking. how was your day?

thanks for the points btw :)

4 0
2 years ago
Read 2 more answers
A computer programmer has an 18% chance of finding a bug in any given program. What is the probability that she does not find a
LiRa [457]

Answer:  (\frac{41}{50})^{10}

Step-by-step explanation:

Since, According to the question,

The chance of finding a bug in a program = 18%

Thus, the probability of finding the bug in first attempt = \frac{18}{100}=\frac{9}{50}

⇒ The probability of not finding any bug in first attempt = 1 - \frac{9}{50} =\frac{41}{50}

Similarly, in second attempt , third attempt, fourth attempt_ _ _ _ _ tenth attempt, the probability of not finding any bug is also equal to \frac{41}{50}

Thus, the probability that she does not find a bug within the first 10 programs she examines

= \frac{41}{50}\times \frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}

= (\frac{41}{50})^{10}

5 0
3 years ago
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