Answer:
0.46
Step-by-step explanation:
42.78/m = 93
=> m = 42.78/93
=> m = 0.46
Hope my answer helps :)
The first five terms of the sequence are; 4,600, 4,550, 4,500, 4,450, 4,400 and the total predicted number of sold cars for the first year is 51,900 cars
<h3>Arithmetic sequence</h3>
- First month, a = 4,600 cars
- Common difference, d = -50 cars
First five terms;
a = 4,600
a + d = 4600 + (-50)
= 4600 - 50
= 4,550
a + 2d
= 4600 + 2(-50)
= 4600 - 100
= 4,500
a + 3d
= 4,600 + 3(-50)
= 4,600 - 150
= 4,450
a + 4d
= 4600 + 4(-50)
= 4,600 - 200
= 4,400
cars predicted for the twelfth month.
a + 11d
= 4600 + 11(-50)
= 4600 + 550
= 4,050
Total predicted number of sold cars for the first year:
Sn = n/2{2a + (n - 1)d }
= 12/2{2×4600 + (12-1)-50}
= 6{9200 + 11(-50)}
= 6(9,200 - 550)
= 6(8,650)
= 51,900 cars
Learn more about arithmetic sequence:
brainly.com/question/6561461
#SPJ1
The equivalent expressions of 22c + 33d are (a), (c) and (e)
<h3>How to determine the equivalent expressions?</h3>
The expression is given as:
22c + 33d
Factor out 11 from the expression
11(2c + 3d)
Multiply by 1
1 * 11(2c + 3d)
Express 1 as -1 * -1
-1 * -1 * 11(2c + 3d)
Evaluate the product
(-11) * (-2c - 3d)
Also, we have:
22c + 33d
Multiply by 1
(22c + 33d) * 1
Express 1 as 3/3
(22c + 33d) * 3/3
Evaluate the product
(66c + 99d) * 1/3
Hence, the equivalent expressions are (a), (c) and (e)
Read more about equivalent expressions at:
brainly.com/question/27911936
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it was fine, thanks for asking. how was your day?
thanks for the points btw :)
Answer: 
Step-by-step explanation:
Since, According to the question,
The chance of finding a bug in a program = 18%
Thus, the probability of finding the bug in first attempt = 
⇒ The probability of not finding any bug in first attempt = 
Similarly, in second attempt , third attempt, fourth attempt_ _ _ _ _ tenth attempt, the probability of not finding any bug is also equal to 
Thus, the probability that she does not find a bug within the first 10 programs she examines
= 
= 