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VladimirAG [237]
2 years ago
9

The angle which is four times its complement is a. 60 b. 30 C. 45 d. 72​

Mathematics
1 answer:
grigory [225]2 years ago
5 0

Answer:

The answer is D.72°

Step-by-step explanation:

hope this helps.

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seropon [69]

Answer:

wow thats hard

Step-by-step explanation:

8 0
2 years ago
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For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
3 years ago
Determine the exact value of sin 13pi/12
ohaa [14]
To answer the problem above, convert the given angle to an equivalent angle with the unit of degrees.
                               (13π / 12 rad) x (360° / 2π) = 195°
We can solve this by directly inputting the value in our scientific calculators. The answer is approximately -0.2588.
6 0
3 years ago
If a number is an element of the set of real
kvasek [131]

Answer:

Option (A)

Step-by-step explanation:

A set of real numbers is a combination of both rational and irrational numbers.

But the elements in the sets of rational and irrational numbers will be different.

In short, rational and irrational number sets are the two subsets of real numbers.

Hence, the number is an element of either the set of rational numbers or the set of irrational numbers.

Option (A) is the correct option.

3 0
3 years ago
For 0° ≤ x &lt; 360°, what are the solutions to sin(StartFraction x Over 2 EndFraction) + cos(x) – 1 = 0 ?
nataly862011 [7]

Answer:

{60°,300°}

b.

Step-by-step explanation:

edge 2020

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3 years ago
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