(2x+6)/10 = (x+6)/8
10(x+6) = 8(2x+6)
10x + 60 = 16x + 48
6x = 12
x = 2
so
AE = 2(2) +6
AE = 4 + 6
AE = 10
Answer:
A1/ ∛m
Step-by-step explanation:
m ^ (-1/3)
this is m to the cubed root in the denominator
1/ ∛m
Answer:
- asymptotes: x = -5, x = 5
- zero: x = 0
Step-by-step explanation:
The function of interest is ...

The asymptotes are found where the denominator is zero. It will be zero when either factor is zero, so at x = 5 and x = -5
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The zeros are found where the numerator is zero. It will be zero for x = 0.
The asymptotes are x=-5, x=5; the zero is x=0.
We get tne n-th term with: tn=1/3tn-1
We know that the first term is t1=81, so 81=1/3t*1-1
81=1/3t-1
82=1/3t
82*3t=1
3t=1/82
t=1/82*3=1/246
The second term is: 1/
2*(1/246)*2)-1
We get the third term by replacing n with 3 and so on...