Using the regression formula with a slope = 2000 and intercept = 15000, what would the predicted income be for someone who has 16 years of education.
Answer:
4.
Step-by-step explanation:
(sec α - tan α)(sec α + tan α) = sec^2 α - tan^2α
But sec^2 α = 1 + tan^2 α so
sec^2 α - tan^2α = 1 + tan^2 α - tan^2α
= 1
so 1 = (sec α - tan α)(sec α + tan α) = 1/4 * x where x is sec α + tan α
1/4 * x = 1
x = 4.
2/3(2/8 + 4/8) = 2/3(1/4 + 1/2)
2/3(3/4) = 1/2
