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Alex787 [66]
3 years ago
12

Given: sin theta=2/3 and is in the second quadrant; evaluate the following expression. sin 2 theta

Mathematics
1 answer:
Dmitry [639]3 years ago
4 0

Answer:The answer to your question is 3. 0

Step-by-step explanation:

Process

1.- Find the cos a

  Opposite side = 5

  Hypotenuse = 13

  Adjacent side = ?

  Adjacent side² = 13² - 5²

                          = 169 - 25

                          = 144

 Adjacent side = 12

cos a = 12/13

2.- Find the sin b

sin b = 5/13

3.- Use the formula below to find sin(a + b)

              sin (a + b) = sina cosb  + sin b cos a

- Substitution

              sin (a + b) = (5/13)((-12/13) + (5/13)/12/13)

- Simplification

              sin (a + b) = -60/169 + 60/13

- Result

              sin(a + b) = 0                        

Step-by-step explanation:

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I NEED HELP WITH THIS QUESTION!!!!
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9514 1404 393

Answer:

  see attached

  (x, y) = (8, 4)

Step-by-step explanation:

The relations given in the problem statement let you write two equations. One for the number of shots, and one for the number of points. The variables x and y are defined in the problem statement.

  x + y = 12 . . . . . total number of shots

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These equations are easily plotted by considering their x- and y-intercepts. The x-intercepts of the equations are found when y=0, so are 12 and 16, respectively.

The y-intercepts are found when x=0, so are 12 and 8, respectively. The two lines are shown in the attached. The first is blue; the second is red. Their point of intersection at (x, y) = (8, 4) is circled.

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7 0
3 years ago
Read 2 more answers
the area of a rectangle is 30 to the square root of 3750 square inches, and the length is 3 to the square root of 250 inches. wh
uranmaximum [27]
<h3><u>Answer</u><u>:</u></h3>

  • \sf { width =10 \sqrt{15} \:inches}

<h3><u>Solution</u><u>:</u></h3>

<em>We are given that:</em>

  • Area of rectangle is 30√3570
  • Length of the rectangle is 3√250

<u>Area </u><u>of </u><u>rectangle </u><u>is </u><u>given </u><u>by:</u>

\implies\quad{\pmb{ \sf{Area = length\times width}} }

<u>Hence, putting the values in the formula:</u>

\implies\quad \sf{ A = l\times w}

\implies\quad \sf{ 30\sqrt{3750}=3\sqrt{250}\times w}

\implies\quad \sf{3\sqrt{250}\times w = 30\sqrt{3750} }

\implies\quad \sf{ w =\dfrac{30\sqrt{3750}}{3\sqrt{250}}}

\implies\quad \sf{ w =10\dfrac{\sqrt{3750}}{\sqrt{250}}}

\implies\quad \sf{ w = 10\times\sqrt{\dfrac{3750}{250}}}

\implies\quad \underline{\underline{\pmb{\sf{ w =10\sqrt{15}}}}}

8 0
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