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3 years ago

Hey again, just need help on the second one, I figured out the first one.

Mathematics

1 answer:

kodGreya [7K]3 years ago

3 0

Answer:

which of the following is the standard from of quadratic equation

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Simplify the expression. Write answer using only positive exponents. (1/3a^3)^-4

Artemon [7]

Answer:

81/a^12

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Is the relation a function? Select Yes or No for each relation.

Lina20 [59]

Hello! There are a few things that determine whether or not something is a function. In this case, to determine whether a relation is a function, we look at the domains, which are the x-coordinates, the first number of the pair. If the number occurs in the x-coordinate for more than one pair in a relation, then it's not a function. If a number only occurs as an x-coordinate once in the relation, then it's a function. In other words, they each have only one y-coordinate in the relation. For this question, the first, second, and third relations are functions. The fourth one is not a function, because the 3 has more than one y-coordinate, so it occurs as an x-coordinate more than once. Here are the answers easier to read.

1st : yes
2nd: yes
3rd: yes
4th: no

3 0

3 years ago

Solve for each equation a)3(x-5)=6 b) 2(x-2/3)=0 c. 4x-5=2-x

Dovator [93]

Answer:

A= 7 B= 0.6 C= 1.4

Step-by-step explanation:

go to m a t h w a y . c o m

8 0

3 years ago

Read 2 more answers

Consider the equation 360=__+84. Use the bar diagram to represent the equation. Then solve for the unknown value.

Andreyy89

Answer:

the answeris 276. 276+84=360.

Step-by-step explanation:

you would subtract 84 from 360 and then you have your answer!!

5 0

3 years ago

In a circle, area and circumference can be found using the formulas A=(pi)r^2 and C=2(pi)r, respectively, Write a formula for A

AURORKA [14]

Answer:

$A = \dfrac{C^2}{4\pi}$

Step-by-step explanation:

Given that

Area of a circle $A=\pi r^2$

Circumference of the circle $C = 2 \pi r$

Let us re-write the equation of area of circle:

$A=\pi r^2$

$A = \pi \times r \times r$

Multiplying and dividing with 2:

$A = \dfrac{2\pi r}{2} \times r\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C}{2} \times r\\\text{Multiplying and dividing by } 2\pi:\\\Rightarrow A = \dfrac{C}{2} \times \dfrac{2\pi r}{2\pi}\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C \times C}{4 \pi}\\\Rightarrow A = \dfrac{C^2}{4 \pi}$

Hence, A in terms of C can be represented as:

$A = \dfrac{C^2}{4\pi}$

4 0

3 years ago