Answer:
Explanation:
It is financial stability apex
The unsuccessful winter campaign in Russia exposed Napoleon's army to extreme cold and The French army's inability to master guerilla warfare led to its defeat in the Peninsula War.
The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g
<h3>Determination of mass of 1 mole of (NH₄)H₂PO₄ </h3>
1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g
<h3>Determination of the mass of H in 1 mole of (NH₄)H₂PO₄ </h3>
Mass of H = 6H = 6 × 1 = 6 g
<h3>Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄ </h3>
115 g of (NH₄)H₂PO₄ contains 6 g of H.
Therefore,
57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H
Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄
Learn more about mass composition:
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