3 years ago

A square has side of length y units what is the area?

1 answer:

6 0

We know to find the answer it is l x w
And since it is a square both the l and w are both “y” units so your answer is
y x y or simplified to y^2
(^ symbol means to the power of two)

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WINSTONCH [101]

<h3>Here is your Answer </h3>

$\frac{1}{2} \times - 2 + \frac{1}{3} \times - 5 \\ \\ = \frac{1}{ \cancel2} \times \cancel{- 2} + \frac{1}{3} \times - 5 \\ \\ = 1 \times - 1 + \frac{1}{3} \times - 5 \\ \\ = - 1 + ( - \frac{5}{3} ) \\ \\ = - 1 - \frac{5}{3} \\ \\ = \frac{ - 3 - 5}{3} \\ \\ = \frac{ - 8}{3} = - 2 \frac{2}{3}$

<h3>Hope This Helps You</h3>

8 0

3 years ago

Can someone plz help ☹️☹️☹️

Ket [755]

Answer:

Step-by-step explanation:

x=3x-70

because corresponding angles are congruent

Solve the equation to find x.

4 0

3 years ago

Help out a real dude

Verdich [7]

59.70 for 6 hours of mowing and 1 hour of babysitting !

7 0

3 years ago

Read 2 more answers

Write 0.2 as a fraction in simplest form.

vredina [299]

Answer:

1/5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Help me simplify this, please!!

OlgaM077 [116]

$- \sqrt[3]{2 x^{4} y^{2} } *3 \sqrt[3]{20 x^{5}y } =-3 \sqrt[3]{2 x^{4} y^{2}20 x^{5}y} = \\ \\ =-3 \sqrt[3]{40 x^{9} y^{3} } =-3 \sqrt[3]{2 ^{3}*5* x^{9} y^{3} } = \\ \\ =-3*2 ^{ \frac{3}{3} } * x^{ \frac{9}{3} } * y^{ \frac{3}{3} } \sqrt[3]{5} =-6 x^{3} y \sqrt[3]{5}$
Answer: B.

6 0

3 years ago