Answer:
18 + 81 = 9(x² + 6x + 9) 11 = (x + 3)²
Explanation:
because This is the value that completes the square. However, since the entire square is multiplied by 9, this value must be multiplied by 9 before we can add it across the equals:
18 + 9 (9) = 9 (x² + 6x + 9)
18 + 81 = 9 (x² + 6x + 9)
99 = 9 (x² + 6x + 9)
Dividing both sides by 9, we have:
11 = x² + 6x + 9
11 = (x + 3) ²
Not really it just makes you tired
So using a(2)=0 we can first solve for k by substituting t for 2
0 = (2-k)(2-3)(2-6)(2+3)
0 = (2-k)(-1)(-4)(5)
0 = (2-k)20
0 = 40 - 20k
-40 = -20k
k = 2
The next step would be to find all the 0s of a.
0 = (t-2)(t-3)(t-6)(t+3)
T = 2,3,6,-3
Then we find the product
2x3x6x-3 = -108
Since the problem asks for the absolute value, the answer is positive 108
Sample Response:
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Hope this helped! :3
