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tatuchka [14]
2 years ago
15

I'll give brainiest to the first correct answer

Mathematics
1 answer:
Elanso [62]2 years ago
6 0

Answer: the first one is the answer I think

Step-by-step explanation:

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MAVERICK [17]
Standard deviation I think
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3 years ago
Write the equation of the line that passes through the point (3,5) and is perpendicular to the line y=3.
3241004551 [841]

Answer:

x = 3

Step-by-step explanation:

y = 3 is the equation of a horizontal line parallel to the x- axis.

A line perpendicular to it must therefore be a vertical line parallel to the y- axis with equation

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (3, 5) with x- coordinate 3 , thus

x = 3 ← equation of perpendicular line

6 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
A winter jacket cost $200. It is on sale for 30% off when you have a coupon to save another 20%. How much do you have to pay for
Luba_88 [7]

Answer:

$100

Step-by-step explanation:

20%+30% = 50% off

50/100 = 1/2

200*1/2 = $100

5 0
3 years ago
Read 2 more answers
What is the sum of the angles 'a' and 'b' from the diagram below.
VikaD [51]

Answer:

90+ 135= 225

Step-by-step explanation:

a can be found with formula (n-2)×180/n, where n is number of sides

a= 135

b=90

3 0
2 years ago
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