I think its Philadelphia hopes this helps...
The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
<em>x = 9</em>
Step-by-step explanation:
The standard form of equation of a line is expressed as y = mx+c
m is the slope
c is the y intercept
Note that the line does not have a slope and the x intercept of the line is a point where the line cuts the x axis. Hence the equation of the line will be expressed as x = c where c is the x intercept;
<em>From the graph, the x intercept =9. Hence the equation of the given line is x = 9</em>
1. 9 is the mode
2. 17.7 is the mean
3. 25.5 is the median
4. mean > median
5. 28 is the range
I’m ok lots of school work
