Locate the foci of ellipse. Show your work. X^2/36 +y^2/11 =1

1 answer:

6 0

<span>In this equation, 36>11 and so the ellipse has major axis along x axis
standard equation of ellipse with major axis is along x axis
x^2/a^2+y^2/b^2=1,
the foci are at (ae,0) and (–ae,0)
eccentricity e is given by
ae=√(a^2-b^2)

In this case ae=√(36-11)= √25=+/- 5

Focii are(-5,0) and(5,0) </span>

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