The hypothesis test shows that we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%
<h3>What is the claim that the return rate is less than 20% by using a statistical hypothesis method?</h3>
The claim that the return rate is less than 20% is p < 0.2. From the given information, we can compute our null hypothesis and alternative hypothesis as:


Given that:
Sample size (n) = 6965
Sample proportion 
The test statistics for this data can be computed as:



z = -2.73
From the hypothesis testing, since the p < alternative hypothesis, then our test is a left-tailed test(one-tailed.
Hence, the p-value for the test statistics can be computed as:
P-value = P(Z ≤ z)
P-value = P(Z ≤ - 2.73)
By using the Excel function =NORMDIST (-2.73)
P-value = 0.00317
P-value ≅ 0.003
Therefore, we can conclude that since P-value is less than the significance level at ∝ = 0.01, we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%
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The division equation that has a quotient of 13 is 1/1/13 = 13
<h3>How to determine the equation?</h3>
The given parameters are:
- Quotient = 13
- Dividend = Whole number
- Divisor = Unit fraction i.e. 1/n where n is an integer.
A division equation is represented as:
Dividend/Divisor = Quotient
Substitute 13 for the Quotient
Dividend/Divisor = 13
Recall that:
Unit fraction = 1/n
So, we have:
Dividend/1/n = 13
Let n = 13.
So, we have:
Dividend/1/13 = 13
This gives
13 * Dividend = 13
Divide both sides by 13
Dividend = 1
So, we have:
1/1/13 = 13
Hence, the division equation is 1/1/13 = 13
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Joel's work makes $9.50/ hr. During the 2 Day, 11 hrs shift, he earns a total of $217.55 but spends a cash of $9 on his bus. Therefore, the money left is $208.55. While on his 4 day, 6 hrs shift, he earns a total of $228 but spends $18, with a total money of $210. The option that he should take to make the most money is the 4 days for 6 hrs shift.
Answer:
The length of the field on the drawing is 55 cm.
Step-by-step explanation:
Given:
Mark made a scale drawing of a soccer field.
Using a scale of .5 cm=1 m.
The actual length of the field is 110 m.
Now, to find the length of the field on drawing.
Let the length of the field on drawing be 
As given 0.5 cm is equivalent to 1 m.
Thus,
is equivalent to 110 m.
Now, to get the length of the field on drawing by using cross multiplication method:

<em>By cross multiplying we get:</em>
⇒ 
⇒ 
Therefore, the length of the field on the drawing is 55 cm.
Answer:
158cm
Step-by-step explanation:
154+162=316
316/2=158