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Sonbull [250]
3 years ago
5

Use the equation to complete an algebraic proof that proves the answer is x = 7/6. Write your proof in your journal and upload y

our answer. You will be awarded 5 points for the statements and 5 points for the reasons.
(2x+6)/5=4x−3
Mathematics
1 answer:
Ivahew [28]3 years ago
4 0

Answer:

x=7/6

Step-by-step explanation:

subtract the 4x from both sides of the equation

(2x+6)-4x=4x-3-4x

find common denominator

(2x+6)/5+(5(-4)x)/5=4x-3-4x

then combine fractions

(2x+6+5(-4)x)/5=4x-3-4x

then multiply the 5&4

(2x+6-20x)/5= 4x3-4x

combine terms

(-18x+6)/5= -3

then multiply everything by 5

-18x+6= -15

subtract the 6 from both sides

-18x= -21

divide -21 by -18

(-21)/(-18)=x

find greatest common multiple (3) and solve

x = 7/6

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Solve the inequality (question 30 please, already solved others)
STALIN [3.7K]

\bf \cfrac{1}{4}n+12 \geqslant \cfrac{3}{4}n-4\implies \cfrac{1}{4}n+16 \geqslant \cfrac{3}{4}n\implies 16\geqslant \cfrac{3n}{4}-\cfrac{1n}{4}\implies 16\geqslant \cfrac{3n-1n}{4} \\\\\\ 16\geqslant\cfrac{2n}{4}\implies 16\geqslant \cfrac{n}{2}\implies 32 \geqslant n

4 0
3 years ago
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Suppose you toss a fair coin 10 times, let X denote the number of heads. (a) What is the probability that X=5? (b) What is the p
zubka84 [21]

Answer:  The required answers are

(a) 0.25,    (b) 0.62,    (c) 6.

Step-by-step explanation:  Given that we toss a fair coin 10 times and X denote the number of heads.

We are to find

(a) the probability that X=5

(b) the probability that X greater or equal than 5

(c) the minimum value of a such that P(X ≤ a) > 0.8.

We know that the probability of getting r heads out of n tosses in a toss of coin is given by the formula of binomial distribution as follows :

P(X=r)=^nC_r\left(\dfrac{1}{2}\right)^r\left(\dfrac{1}{2}\right)^{n-r}.

(a) The probability of getting 5 heads is given by

P(X=5)\\\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}\\\\\\=\dfrac{10!}{5!(10-5)!}\dfrac{1}{2^{10}}\\\\\\=0.24609\\\\\sim0.25.

(b) The probability of getting 5 or more than 5 heads is

P(X\geq 5)\\\\=P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)\\\\=^{10}C_5\left(\dfrac{1}{2}\right)^5\left(\dfrac{1}{2}\right)^{10-5}+^{10}C_6\left(\dfrac{1}{2}\right)^6\left(\dfrac{1}{2}\right)^{10-6}+^{10}C_7\left(\dfrac{1}{2}\right)^7\left(\dfrac{1}{2}\right)^{10-7}+^{10}C_8\left(\dfrac{1}{2}\right)^8\left(\dfrac{1}{2}\right)^{10-8}+^{10}C_9\left(\dfrac{1}{2}\right)^9\left(\dfrac{1}{2}\right)^{10-9}+^{10}C_{10}\left(\dfrac{1}{2}\right)^{10}\left(\dfrac{1}{2}\right)^{10-10}\\\\\\=0.24609+0.20507+0.11718+0.04394+0.0097+0.00097\\\\=0.62295\\\\\sim 0.62.

(c) Proceeding as in parts (a) and (b), we see that

if a = 10, then

P(X\leq 0)=0.00097,\\\\P(X\leq 1)=0.01067,\\\\P(X\leq 2)=0.05461,\\\\P(X\leq 3)=0.17179,\\\\P(X\leq 4)=0.37686,\\\\P(X\leq 5)=0.62295,\\\\P(X\leq 6)=0.82802.

Therefore, the minimum value of a is 6.

Hence, all the questions are answered.

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4 years ago
an aircraft flew 5 hours with the wind. the return trip took 6 hours against the wind. if the speed of the plane in still air is
olga2289 [7]

w = 37.846 mph (wind rate)
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3 years ago
Find the sum of the series and show your process for finding each term leading to the final sum.
Crazy boy [7]

ANSWER

\sum_{k=3}^5( - 2k + 5) =  - 9

EXPLANATION

The given series is

\sum_{k=3}^5( - 2k + 5)

This series is finite.

The expanded form is

\sum_{k=3}^5( - 2k + 5) = ( - 2 \times 3 + 5) + ( - 2 \times 4 + 5) + ( - 2 \times 5 + 5)

This simplifies to

\sum_{k=3}^5( - 2k + 5) = ( - 6 + 5) + ( - 8+ 5) + ( - 10+ 5)

\sum_{k=3}^5( - 2k + 5) = ( - 1) + ( - 3) + ( - 5)

\sum_{k=3}^5( - 2k + 5) =  - 9

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Answer:

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Step-by-step explanation:

So you take -6 and subtract another 11, that gives you negative 17.

Hope This Helps! If it doesn’t let me know and I can explain it more in depth.

7 0
3 years ago
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