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Burka [1]
3 years ago
6

Can you help me with this question. 2a when a is equal to -3

Mathematics
2 answers:
Katarina [22]3 years ago
8 0

Answer:

-6

Step-by-step explanation:

2*(-3)= -6

solong [7]3 years ago
5 0
2(-3) = -6, is the answer
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A square has a perimeter of 40 feet. Find the length of the diagonal of the square.
Stells [14]

Answer:

10 root 2

Step-by-step explanation:

Refer to attachment.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>

4 0
3 years ago
For the line that passes through Y(3,0), parallel to DJ with D(-3,1) and J(3,3), complete the following: Find the slope. Write a
Ulleksa [173]

I am going to graph the situation on an external graphing utility and show you the answer, it will take a

minute, stay with me.

m\text{ = }\frac{rise\text{ }}{\text{run}}=\frac{change\text{ in y}}{\text{change in x}}=\frac{3}{1}=3y\text{ = mx+b}\rightarrow\text{ b =-1}

So the equation of the line is.

y\text{ =3x -1}y\text{ -1 = m(3-0)}

8 0
2 years ago
The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width , what are the dimensions?
lianna [129]
Let the length be \ell and the width be w. Now, write the length in terms of the width. "The length is 15 cm. less than twice the width" in the form of an equation is

\ell = 2w - 15 cm.

Let's plug that into the equation for the perimeter now. The perimeter of a rectangle is 2 \ell + 2w, so the equation for the perimeter of this rectangle is

2 \ell + 2w = 102 cm.

Plugging in the length in terms of width and solving for the width, we get

2(2w - 15 cm.) + 2w = 102 cm.
6w - 30 cm. = 102 cm.
6w = 132 cm.
\bf w = 22 cm.

To find the length, we just have to plug in the width into the equation we wrote for the length in terms of the width:

\ell = 2w + 15 cm.
\ell = 2(22 cm.) - 15 cm.
\bf \ell = 29 cm.
7 0
3 years ago
Write each fraction or mixed number as a decimal <br><img src="https://tex.z-dn.net/?f=1%20%5Ctimes%20%5Cfrac%7B1%7D%7B2%7D%20"
12345 [234]
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6 0
3 years ago
Complete each congruency statement and name the rule used. If you cannot show the triangles are congruent from the given informa
irinina [24]

Answer:

The correct answer is;

ΔANT ≅ ΔFLE by the SIde-Side-Side (SSS) rule of congruency

Step-by-step explanation:

The given information are;

Segment TN is congruent ts segment EL

Segment TA is congruent ts segment EF

Segment AN is congruent ts segment FL

Therefore, triangle ΔANT is congruent to ΔFLE by the Side-Side-Side (SSS) rule of congruency

One of the rule used to serve as proof that two or more triangles are congruent, is the Side-Side-Side (SSS) rule of congruency. The Side-Side-Side rule of congruency states that if the dimensions of the three sides of one triangle are equal to the dimensions of the three sides of another triangle, the two triangles are congruent.

Therefore, the correct option is ΔANT ≅ ΔFLE by the Side-Side-Side (SSS) rule of congruency

7 0
3 years ago
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