May someone help me plz :(

Simplify: (10m^2+6mx−11x^2)+(−2m^2+4mx+4x^2).

a_sh-v [17]

Answer: 8m^2 - 7x^2 + 10mx

Step-by-step explanation:

7 0

3 years ago

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A correlation where the x-value increases and the y-value increases is called a __________.

IrinaK [193]

Answer:

positive correlation

Explanation:

The correlation in where x and y value increases makes a line going upwards to the right side. This means that it is a positive correlation.

8 0

4 years ago

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What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ? Enter your answer in t

nikdorinn [45]

Let

$A(-12,2)\\B(6,2)\\C(-2,-3) \\D(-20.-3)\\E(-12.-3)$

using a graphing tool

see the attached figure to better understand the problem

we know that

Parallelogram is a quadrilateral with opposite sides parallel and equal in length

so

$AB=CD \\AD=BC$

The area of a parallelogram is equal to

$A=B*h$

where

B is the base

h is the height

the base B is equal to the distance AB

the height h is equal to the distance AE

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-12,2)\\B(6,2)$

substitute the values

$d=\sqrt{(2-2)^{2}+(6+12)^{2}}$

$d=\sqrt{(0)^{2}+(18)^{2}}$

$dAB=18\ units$

Step 2

Find the distance AE

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-12,2)\\E(-12.-3)$

substitute the values

$d=\sqrt{(-3-2)^{2}+(-12+12)^{2}}$

$d=\sqrt{(-5)^{2}+(0)^{2}}$

$dAE=5\ units$

Step 3

Find the area of the parallelogram

The area of a parallelogram is equal to

$A=B*h$

$A=AB*AE$

substitute the values

$A=18*5=90\ units^{2}$

therefore

the answer is

the area of the parallelogram is $90\ units^{2}$

5 0

3 years ago

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Solve each equation by taking square roots 10p^2 +20=1490

dimulka [17.4K]

$10p^2 +20=1490$

$
10p^2=1490-20
 
$ $Subtract \ 20 \ from \ both \ sides$

$10p^2=1470

 
$

$p^2= \dfrac{1470}{10}$ $Divide \ both \ sides \ by \ 10$

$p^2=147$

$p=+ \sqrt{147}$ $Take \ the \ square \ root \ of \ both \ sides$

$p=+7 \sqrt{3}$

3 0

3 years ago

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To get to work Sam jogs 3 kilometers to the train, then rides the remaining 5 kilometers. If the train goes 40 km per hour faste

cupoosta [38]

Let
r = Sam's jogging rate
r+40 = train's rate

The rate refers to a speed of any moving body.
Know first the relationship of distance, time, and rate. The time is the distance divided by the rate.
By analyzing the problem, the time for Sam and the time for train have the total time of 30 minutes or 1/2 hours. Expressing it into an equation yields
t(Sam) + t(train) = 1/2 hours
The distance covered by Sam is 3 km, and the distance covered by train is 5 km. So
3/s + 5/(s+40) = 1/2
Solving for s,
3(s+40) + 5s = (1/2)*(s(s+40))
3s + 120 + 5s = (1/2)s² + 20s
8s + 120 = (1/2)s² + 20s
(1/2)s² + 12s - 120 = 0

The solution is turned out into a quadratic equation. If you know the quadratic formula, you get for x, for instance the two values of x are
s = 7.59 and s = -31.59

The value s = -31.59 is meaningless. Therefore Sam's jogging rate is 7.59 km/hr.

4 0

3 years ago

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