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natta225 [31]
3 years ago
5

Please solve this problem please give me the correct answer​

Mathematics
1 answer:
barxatty [35]3 years ago
8 0

I hope this solution works

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What is the fourth term of an arithmetic sequence whose first term is 23 and whose seventh term is 5?
mixas84 [53]

We have that  the fourth term of an arithmetic sequence is

a_4=14

Option C

From the question we are told

What is the fourth term of an arithmetic sequence whose first term is 23 and whose seventh term is 5?

A) 78

B) 32

C) 14

(Explain your work)

Generally the equation for the  arithmetic sequence  is mathematically given as

a_4=a_1+(n-1)d

Therefore

For seventh term

5=23+(6)d\\\\d=5-23/(6)\\\\d=-3

Therefore

For Fourth term

a_4=23+(3*(-3))

a_4=14

For more information on this visit

brainly.com/question/23366835

4 0
3 years ago
A jar contains 550 beans. Of all the beans, 2/5 are white beans and the rest are navy beans. What is the ratio of white beans to
LenKa [72]

Answer:

2/5 are white so 3/5 are navy

Step-by-step explanation:

4 0
3 years ago
F(x) = 2(x + 4)^2 (x - 2)​
Kryger [21]

Answer:

3

Step-by-step explanation:

hope it helpz >-<

7 0
3 years ago
Read 2 more answers
Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w
Arte-miy333 [17]
Let k be an integer. Suppose there is a triangle with legs of length 16 and 2k+1. Then by the Pythagorean theorem, the length of the hypotenuse should be

\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}

The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if x=16 and y=2k+1 are integers, then so are x^2-y^2, 2xy, and x^2+y^2.

However, 4k^2+4k+257 is not a perfect square trinomial, which means for any integer k, the length of the hypotenuse is not an integer, so such a triangle doesn't exist.
4 0
3 years ago
Plz help me their is a picture
11111nata11111 [884]

Answer:

simple. y=x+2

Step-by-step explanation:

:) ======

3 0
2 years ago
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