Answer:
True, based on the <em>Transitive Property of Equality</em>.
Step-by-step explanation:
Note that the <em>Transitive Property of Equality </em>states that "If a = b, & b = c, then a = c.
In this case it is the same.
∠1 ≅ ∠2 (because both are complementary), ∠1 ≅ ∠3 (again, both are complementary), then based on the Transitive Property, ∠2 ≅ ∠3, making all of them complementary angles
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<em>~Senpai</em>
Answer:
The answer to your question is the second option 
Step-by-step explanation:
Expression
![[\frac{(x^{2}y^{3})^{-2}}{(x^{6}y^{3}z)^{2}}]^{3}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%28x%5E%7B2%7Dy%5E%7B3%7D%29%5E%7B-2%7D%7D%7B%28x%5E%7B6%7Dy%5E%7B3%7Dz%29%5E%7B2%7D%7D%5D%5E%7B3%7D)
Process
1.- Divide the fraction in numerator and denominator
a) Numerator
[(x²y³)⁻²]³ = (x⁻⁴y⁻⁶)³ = x⁻¹²y⁻¹⁸
b) Denominator
[(x⁶y³z)²]²= (x¹²y⁶z²)³ = x³⁶y¹⁸z⁶
2.- Simplify like terms
a) x⁻¹²x⁻³⁶ = x⁻⁴⁸
b) y⁻¹⁸y⁻¹⁸= y⁻³⁶
c) z⁻⁶
3.- Write the fraction
The integer would be
positive 5
Answer:
x=2
Step-by-step explanation:
4( 2+x) = 18-x
8 + 4x = 18 - x
4x+x = 18-8
5x= 10
x=2
