$6b+bx=ax+a^2\implies 60-a^2+bx=ax\implies 60-a^2=ax-bx \\\\\\ \stackrel{\underset{\qquad \downarrow }{\textit{common factoring}}}{60-a^2=x(a-b)}\implies \cfrac{60-a^2}{a-b}=x$

8 0

2 years ago

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Y+ 1/2 =-3/4 How would you do this one

UkoKoshka [18]

$y+\frac{1}{2}=-\frac{3}{4}\ \ \ |Add\ \frac{1}{2}\ to\ each\ side\\\\
y=-\frac{3}{4}-\frac{1}{2} \ \ \ |Make\ a common\ denominator\\\\
y=-\frac{3}{4}-\frac{2}{4}\\\\
y=-\frac{5}{4}=-1\frac{1}{4}\\\\
y=-1\frac{1}{4}$

6 0

3 years ago

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Average movie prices in the United States are, in general, lower than in other countries. It would cost $79.00 to buy three t

Lady bird [3.3K]

Answer:

It would cost $79.31 to buy three tickets in Japan plus two tickets in Switzerland. Three tickets in Switzerland plus two tickets in Japan would cost $74.79.

Step-by-step explanation:

6 0

2 years ago

A wheel has 10 equally sized slices numbered from 1 to 10.

Ksenya-84 [330]

The random probability of event X, wheel stopping on a white slice is 0.9 while the probability of not X, wheel stopping on Grey slice is 0.1

Total numbers on wheel = total possible outcomes = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

Grey colored portion = {3}

White colored portion = {1, 2, 4, 5, 6, 7, 8, 9, 10}

X = Event that wheel stops on a white slice

P(X) = number of white slices ÷ total number of slices

P(X) = 9 / 10 = 0.9

P(not X) = 1 - P(X)

P(not X) = 1 - 0.9 = 0.1

Therefore, the probability that wheel stops on a white slice is 0.9 while, the probability that wheel does not stop on a white slice is 0.1

Learn more :brainly.com/question/18153040

4 0

3 years ago