Answer:
output is -17
Step-by-step explanation:
x is input, y is output. You do y = -24 + 7
then y = -17
$$ −\frac{7}{10} \div\frac{2}{5}= \frac{-7}{4} $$ . totally answer. I hope helping with this answer
Answer:
$1.50
Step-by-step explanation:
To find the best deal, we first want to consider price per unit. To find the price per unit, we divide the price by the number of units. For the 10 shin guard package, our price is 14.50, and we divide that by 10 to get 1.45 . Therefore, our unit price for the package of 10 is $1.45 per shin guard. Similarly, we can find the unit price for the package of 15 to be 22.5/15 = $1.50 per shin guard. As 1.50 is greater than 1.45, the lowest unit price is for the package of 10.
The question is asking for us to compare the prices if we bought 30 of each. For the package of 10, we get 1.45*30 (as we're buying 30 for 1.45) = 43.5 as the total price, and for the package of 15, we get 1.5*30 = 45 as our price. As 15 and 10 are both factors of 30, we don't need to worry about converting it back into packages of 10/15. The difference between buying 30 at the lowest and highest unit price is therefore (45-43.5)=1.5 dollars
Answer:
give or take 5 miles.
Step-by-step explanation:
im not shor but that is true about the both of them
Answer:
If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:
(x,-y)
So we only change the sign of the y-component.
Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.
Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.
The original vertices are:
C = (-3, 7)
D = (0, 7)
E = (0, 10)
F = (-3, 10)
Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:
C' = (-3, -7)
D' = (0, -7)
E' = (0, - 10)
F' = (0, - 10)
Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.