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3 years ago

5

Please help 20 Pts...

2 answers:

storchak [24]3 years ago

8 0

Step-by-step explanation:

5/4,1.25

ok po itry my best

Aliun [14]3 years ago

4 0

Answer:

2

1–

2

Step-by-step explanation:

its my answer i don't know if my answer is right

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In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz

Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a $\frac{1}{4} = 0.25$ probability of getting ir right. So $\pi = 0.25$ . There are five questions, so $n = 5$ .

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

$P = 0.75(0.25) = 0.1875$

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: $P = P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955$

$P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637$

$P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592$

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

$P = P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879$

$P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146$

$P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001$

$P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035$

There is a 10.35% probability that she gets the majority of the questions right.

6 0

3 years ago

What is the answer to 5m + 30 = 60

Keith_Richards [23]

Answer:

m = 6

Step-by-step explanation:

Given

5m + 30 = 60 ( subtract 30 from both sides )

5m = 30 ( divide both sides by 5 )

m = 6

6 0

3 years ago

A 30 feet ladder is leaning against the wall. The top of the ladder is resting 25 feet on the building. How far is the base of t

g100num [7]

Answer:

16.58 feet

Step-by-step explanation:

a² + b² = c²

Think of this as a right triangle

The hypotenuse is 30, and one of the legs is 25

To find the other leg, subtract the square of the hypotenuse by the square of the given leg

30² - 25² = leg

900 - 625 = 275

Square root the answer to find the length of the missing leg

√275 = 16.583123951777

The leg is 16.58 ft.

6 0

2 years ago

Which of the following pairs of fractions are equivalent?

AlekseyPX

D: 1/6 * 2 = 2/12

hope this helps :) (please mark brainliest!)

3 0

3 years ago

60 people attend a game night. Everyone chooses to play chess, a two-player game, or cribbage, a four-player game All 60 people

zysi [14]

Answer:

A=52

B=48

C=45

D=58

Step-by-step explanation:

To find the variables just do 60 minus the number they give. For example, to find A, you do 60-8.

Hope this helps :)

5 0

2 years ago