Answer: $96.8
Step-by-step explanation:
Formular for Compounding annually :
A =P ( 1 + r/n) ^nt
Where p is the Principal given as $80
r is the rate given as 10% = 10/100 = 0.1
n is the number of times the principal was compounded, given as 1
t is the time, given as 2 years:
Slot the values into the formula:
A= $80 ( 1 + 0.1/1) ^ (1 × 2)
A= $80 ( 1 + 0.1) ^2
A= $80 ( 1.1) ^2
A= $80 (1.21)
A= $80 x 1.21
A= $96.8
96.8 is already rounded to the nearest cent.
Answer:
The sequence diverges.
Step-by-step explanation:
A sequence
converges when
is a real number.
In this question, the sequence given is:

The cosine is always going to be between -1 and 1, so for the convergence of the sequence, we look it as:
. So

Since the limit is not a real number, the sequence diverges.
No, the probability of getting a 5 is 1/6, but you could roll any number of fives in a row. It is just as likely to get rolled the second time as it was the first.
Answer:
Step-by-step explanation:
Hello!
For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.
In this example the variable is:
X: height of a college student. (cm)
There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.
The option you have is to apply the Central Limit Theorem.
The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.
As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.
The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:
X[bar]~~N(μ;σ2/n)
Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:
98% CI
1 - α: 0.98
⇒α: 0.02
α/2: 0.01

X[bar] ± 
174.5 ± 
[172.22; 176.78]
With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].
I hope it helps!
Answer:
4.62
Step-by-step explanation:
using the distance formula plug in the 6
6=-8cos(pi/6 t)