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3 years ago

Someone pls help “What is the equation of this graph?”

Mathematics

1 answer:

olchik [2.2K]3 years ago

8 0

f(x) = -x +1

we can test a couple points

f(0) = -(0) +1 = 1

f(1) = -(1) +1 = 0

f(2) = -(2) +1 = -1

<u>RATE BRAINLIEST</u>

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3 years ago

Read 2 more answers

What is 5 3/4x -2 2/9

sergeinik [125]

$\displaystyle\\5\frac{3}{4}\times\left(-2\frac{2}{9}\right)=\\\\\\=-\frac{5\times4+3}{4}\times\frac{2\times9+2}{9}=\\\\\\=-\frac{23}{4}\times\frac{20}{9}=-\frac{460}{36}=-\frac{115}{9}=\boxed{\bf12\frac{7}{9}}$

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3 years ago

Please help me . I need help with this. I’m getting very very frustrated !!! You can get 35 points !

Elden [556K]

Notes:

The sign of the coefficient of the quadratic equation determines if the vertex is a minimum or maximum. Positive looks like ∪ so has a minimum. Negative looks like ∩ so has a maximum.
Maximum/minimum height is the y-value of the vertex.
Time to reach maximum height is the x-value of the vertex (which is also the Axis-Of-Symmetry).

Answer: 4) maximum

5) 20.1 ft

6) 2 seconds

<u>Step-by-step explanation:</u>

4) h(t) = -16t² + 256t

↓

the coefficient is negative so it looks like ∩.

Therefore, it has a maximum.

5) h(t) = -16t² + 30t + 6

$\text{AOS: }x=\dfrac{-b}{2a}\quad \rightarrow \quad x=\dfrac{-(30)}{2(-16)}=\dfrac{-30}{-32}=\dfrac{15}{16}\\\\\\\text{Maximum: }h\bigg(\dfrac{15}{16}\bigg)=-16\bigg(\dfrac{15}{16}\bigg)^2+30\bigg(\dfrac{15}{16}\bigg)+6\\\\\\.\qquad \qquad \qquad \qquad =\dfrac{-225}{16}+\dfrac{450}{16}+\dfrac{96}{16}\\\\\\.\qquad \qquad \qquad \qquad =\dfrac{321}{16}\\\\\\.\qquad \qquad \qquad \qquad \approx20.1$

6) h(t)=-16t²+64t+80

$\text{AOS: }x=\dfrac{-b}{2a}\quad \rightarrow \quad x=\dfrac{-(64)}{2(-16)}=\dfrac{-64}{-32}=2$

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