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2 years ago

Find the value of the expression.

Mathematics

1 answer:

Jlenok [28]2 years ago

5 0

Answer:

according to your question it should be 3.00x 10^18 which is not a choice

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F(x)=|3x+5|+6 g(x)=7 find (f+g) (x).

horrorfan [7]

Answer:

$(f+g) (x)=\mid 3x+5\mid+13$

Step-by-step explanation:

Operation of Functions

Given:

$f(x)=\mid 3x+5\mid+6$

$g(x)=7$

The sum of (f+g) (x) is:

$(f+g) (x)=\mid 3x+5\mid+6+7$

We cannot operate with the expression inside the absolute bars, thus:

$\boxed{(f+g) (x)=\mid 3x+5\mid+13}$

8 0

2 years ago

Inqualtites question Complete the inequality expression that describes this set of numbers:

RideAnS [48]

Answer:

- 3 ≤ x < 0

Step-by-step explanation:

- 3 is included in the set thus x can equal - 3

- 3 is less than all other values in the set including the largest value of 0, thus

- 3 ≤ x < 0

3 0

2 years ago

The dimensions of a plastic container are 8 in x 6 in x 4 in. What is the volume of the container? in3

Rina8888 [55]

Answer:

8 x 6 x 4 = 192

Step-by-step explanation:

Volume is l x w x h

6 0

3 years ago

Read 2 more answers

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

3 years ago

Bob's gift shop sold a record number of cards for Mother's Day. One salesman sold 25 cards, which was 20% of the cards sold for

Rina8888 [55]

Answer:

125 cards

Step-by-step explanation:

20% = 0.2= 1/5

So because 25 is 1/5 0f the total number cards multiply 25 by 4 to get the other 80% and add the first 25 cards to that number.

(25 x 4) + 25= ?

100 + 25 = 125

therefore 125 cards were sold.

8 0

2 years ago