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lana66690 [7]
3 years ago
13

Nêu khái niệm về 4 số lương tử: n, l, mℓ, ms, giá trị và ý nghĩa của nó

Chemistry
1 answer:
Fantom [35]3 years ago
7 0

Answer: Để mô tả hoàn toàn một electron trong nguyên tử, cần bốn số lượng tử: năng lượng (n), mômen động lượng (ℓ), mômen từ (mℓ) và spin (ms).

Số lượng tử đầu tiên mô tả lớp vỏ electron hay mức năng lượng của nguyên tử.

Explanation:

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Pavel [41]
Salt lowers the freezing point, and thus the melting point of the ice
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4 years ago
The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its el
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The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

<h3>What is Empirical Formula ?</h3>

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C            83.87       12                     \frac{83.87}{12} = 6.98                   \frac{6.98}{0.25} = 3

H            11.99         1                       \frac{11.99}{1} = 11.09                  \frac{11.09}{0.25} = 4

O            4.14          16                      \frac{4.14}{16} = 0.25                    \frac{0.25}{0.25} = 1

Thus the empirical formula is C₃H₄O₁.

<h3>How to find the Molecular formula of compound ?</h3>

Molecular formula = Empirical formula × n

n = \frac{\text{Molecular weight}}{\text{Empirical formula weight}}

  = \frac{386.64}{56}

  = 7

Molecular formula = Empirical formula × n

                               = 7 (C₃H₄O₁)

Thus from the above conclusion we can say that The main constituent of gallstones is cholesterol. Cholesterol may have a role in heart attacks and blood clot formation. Its elemental percentage composition is 83.87% C, 11.99% H, and 4.14% O. It has a molecular weight of 386.64 amu. Empirical formula is C₃H₄O₁ and Molecular formula is 7(C₃H₄O₁).

Learn more about the Empirical Formula here: brainly.com/question/1603500

#SPJ4

7 0
2 years ago
A chemist must prepare of hydrochloric acid solution with a pH of at . He will do this in three steps: Fill a volumetric flask a
Eva8 [605]

Answer:

1.7 mL

Explanation:

<em>A chemist must prepare 550.0 mL of hydrochloric acid solution with a pH of 1.60 at 25 °C. He will do this in three steps: Fill a 550.0 mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (8.0 M) stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.</em>

Step 1: Calculate [H⁺] in the dilute solution

We will use the following expresion.

pH = -log [H⁺]

[H⁺] = antilog - pH = antilog -1.60 = 0.0251 M

Since HCl is a strong monoprotic acid, the concentration of HCl in the dilute solution is 0.0251 M.

Step 2: Calculate the volume of the concentrated HCl solution

We want to prepare 550.0 mL of a 0.0251 M HCl solution. We can calculate the volume of the 8.0 M solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 0.0251 M × 550.0 mL/8.0 M = 1.7 mL

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3 years ago
Ap chemistry how to determine if compound is ionic or molecular bqsed on formula
ludmilkaskok [199]
Ionic compound consists of a positively charged ion and a negatively charged anion. For example, NaCl. Na (sodium) is a cation (another word for positively charged ion) and Cl (chloride) is a anion (another way for negatively charged ion.)

Molecular compounds consists of only negatively charged ions. For example Br2I is a compound of 2 elements that are negatively charged.

Unlike ionic compounds, molecular compounds consists of two or more negatively charged elements.  
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Differentiate between Mendeleev's Period law and Modern Periodic law<br>​
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<h2>see in the attachment hope it helps you</h2>

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