<u>Answer:
</u>
The point-slope form of the line that passes through (6,1) and is parallel to a line with a slope of -3 is 3x + y – 19 = 0
<u>Solution:
</u>
The point slope form of the line that passes through the points
and parallel to the line with slope “m” is given as
--- eqn 1
Where “m” is the slope of the line.
are the points that passes through the line.
From question, given that slope “m” = -3
Given that the line passes through the points (6,1).Hence we get 
By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -3 can be found out.
y – 1 = -3(x – 6)
y – 1 = -3x +18
On rearranging the terms, we get
3x + y -1 – 18 = 0
3x + y – 19 = 0
Hence the point slope form of given line is 3x + y – 19 = 0
12^3 / 12^7
Cancel out the common factor:
Multiply the numerator by 1:
12^3 * 1 / 12^7
Factor 12^3 out of the denominator to get:
12^3 * 1 / 12^3 * 12^4
Now cancel the common factor to get:
1/12^4
Answer:
w=14
Step-by-step explanation:
-8(w + 1) = -5(w + 10)
Remove the parentheses
-8w-8+-5w-50
Move terms
-8w+5w=-50+8
Collect like terms and calculate
-3w=-42
Then divide on both sides
Answer:
The best choice is y = 82.1
Step-by-step explanation:
Just simplify both sides of the equation, then isolate the variable.
Which makes it's exact form y= 34^5/4 and when converting it to decimal form it becomes y = 82.1