Answer:
Cost of material is $245.31
Step-by-step explanation:
Let dimension of box,
<em>The length of this base is twice the width.</em>
<em>∴ </em>x = 2y
Volume of box = 10 m³
∴ xyz = 10
⇒ 2y²z = 10
⇒ y²z = 5
<em>Material for the base costs $15 per square meter.</em>
Total cost of base = 15xy
Total cost of base = 30y² [∵ x = 2y ]
<em>Material for the sides costs $9 per square meter.</em>
Total cost of side = 9(2xz+2zy)
Total cost of side = 18(xz+yz)
Total cost of material for container = 30y² + 18(xz+yz)
[From (i)]
Differentiate w.r.t y
For critical point , C'(y)=0
The minimum cost of container material at
Hence, the cheapest cost of material for container is $245.31
Here is the solution for that
<h2>
Explanation:</h2>
Remember that the slope of a line is define by the change in y divided by the change in x. In other words:
We can calculate the slope of any line using two points, so:
From the graph, we know two points:
Therefore, the slope is:
Therefore, the correct option is:
d) slope= -2
58.967 kilograms. "I'm only typing this sentence bc the answer has to be at least 20 characters long"