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-BARSIC- [3]
3 years ago
9

Prove that: sin 70° - sin 50° = sin 10°​

Mathematics
1 answer:
Firlakuza [10]3 years ago
6 0

Step-by-step explanation:

sin α - sin β = 2 cos (α + β)/2 sin (α - β)/2

sin 70° - sin 50° = sin 10°

2 cos (70° + 50°)/2 sin (70° - 50°)/2 = sin 10°

2 cos 120°/2 sin 20°/2 = sin 10°

2 cos 60° sin 10° = sin 10°

2 (½) sin 10° = sin 10°

sin 10° = sin 10° → <u>Proved</u>

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