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2 years ago

Find g(a - 1) when g(x) = 5x - 4.

Mathematics

1 answer:

pishuonlain [190]2 years ago

7 0

Answer:

$g(a-1) = 5a-9$

Step-by-step explanation:

Hi there!

$g(x) = 5x - 4$

Replace all x's with a-1:

$g(a-1) = 5(a-1) - 4\\g(a-1) = 5a-5 - 4\\g(a-1) = 5a-9$

I hope this helps!

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An article is bought for Rs. 125 what is the profit percentage?

Aneli [31]

Step-by-step explanation:

Solution given;

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2 years ago

Which of the following indicates the subtraction property of equality when solving the equation 4(x + 9) + 5 = 3x − 8? Question

jeka94

Answer: 4(x + 9) = 3x − 8 − 5

Step-by-step explanation:

Hi, to answer this question we have to analyze the equation given:

4(x + 9) + 5 = 3x − 8

The subtraction property of equality states that if we subtract the same number from both sides of the equation, the equality remains.

So, if we subtract 5 from both sides:

4(x + 9) + 5-5 = 3x − 8 -5

4(x + 9) = 3x − 8 − 5

Feel free to ask for more if needed or if you did not understand something.

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3 years ago

D Evaluate arcsin (6)] at x = 4. dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

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Answer:

Step-by-step explanation:

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