A girl runs 40 m, west, 50 m south, 60 m, east. what is his net displacement?
1 answer:
The displacement of the girl which the relative change in her position from her starting point. Therefore, the shortest distance between her initial and final position is 58.85 m North - West
From the sketch of the girls movement attached below, the displacement of the girl can be calculated thus :
Using Pythagoras :
Displacement, d = √(50² + 20²)
d = √(2500 + 400)
d = √2900
d = 53.851
Therefore, the displacement of the girl, which is the shortest distance between her current position and starting position is 53.85 meters NW.
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Answer:
Attached
Explanation:
The equation given is;
3y-7=0
3y=7
y=7/3
Using a graph tool to plot the equation , the graph will be as attached;
