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3 years ago

6

I need help now I don't get this

2 answers:

elena-14-01-66 [18.8K]3 years ago

6 0

The answer would be $1.80. 25% off of $3.00 is $2.25 and 20% off that is $1.80

Darina [25.2K]3 years ago

3 0

The answer is $1.80. You would take 25% of 3, which is 75, and subtract it from 3. That leaves you with $2.25, which you take 20% off, which is 0.45, and subtract that from 2.25. That leaves you with a grand total of $1.80. Hope that this helped!

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This one is hard! try your best please.

user100 [1]

Answer:

1. 301.6 $in^{3}$

2. 576 $in^{3}$

3. 274.41 $in^{3}$

Step-by-step explanation:

We know that the diameter of one of the spheres must be 4 in, because the length of the box is 12 in and there are 3 spheres along each side, and $\frac{12}{3} =4$ . That means that the radius of a sphere is 2 in. Put 2 into the formula for the volume of a sphere, and then multiply your solution by 9, to get the total volume.

Then, you can find the volume of the box, because you know its dimentions are 12x12x4.

Subtract your answer for part 1 from your answer for part 2, and you have the solution to part 3. Hope this helps!! :-)

3 0

2 years ago

IF KOBE HAD 8 DUNKS AND LEBRON HAD 10, HOW MANY MORE DUNKS DID LEBRON HAVE THEN KOBE?

pav-90 [236]

Answer:

2

Step-by-step explanation:

10-8

6 0

3 years ago

Read 2 more answers

Find the missing value given (-1,7)(-3,d) m= 6 HELP ASAP WILL MAKE BRAINLEST

-Dominant- [34]

Answer:

d= -5

Step-by-step explanation:

The slope of a line is found by finding the ratio of change is y values to change is x values

$m=y_2-y_1/x_2-x_1$

The points on the line have coordinates at: (-1,7) (-3,d)

where ;

$y_2=d, y_1=7,x_2=-3,x_1=-1,m=6$

Applying the formula with values as;

$6=\frac{d-7}{-3--1} \\\\6=\frac{d-7}{-3+1} \\\\6=\frac{d-7}{-2} \\\\6*-2=d-7\\\\-12=d-7\\\\-12+7=d\\\\-5=d$

The value of d = -5

The coordinates of the points (-1,7) (-3,-5)

6 0

3 years ago

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

8 0

3 years ago

Is 4/12more or less than 4/6

11111nata11111 [884]

4/12 is less than 4/6

4/12 = 2/6

and 2/6 < 4/6

5 0

3 years ago

Read 2 more answers