All categories

2 years ago

3. Tiffani has a baseball

Mathematics

1 answer:

Nimfa-mama [501]2 years ago

3 0

Answer:

Tiffani has 182 cards left.

Step-by-step explanation:

Find one-third (1/3) of 273:

1/3 x 273 = 91

Therefore, she sells 91 cards.

273 - 91 = 182 cards left

Hope this helps :)

You might be interested in

Priscilla can make 3 bracelets in 15 minutes. At this rate, how many bracelets can she make in 30 minutes?

BigorU [14]

Answer:

6 bracelets

Step-by-step explanation:

If she can make 3 in 15, just multiply by 2 to get 30 minutes. Therefore she can make 6 bracelets in 30 minutes.

7 0

2 years ago

Read 2 more answers

Find the area of the rhombus

Ugo [173]

Answer:a=81/2 or 40.5

Step-by-step explanation:

(d1 x d2)/2=a

6 0

3 years ago

Read 2 more answers

I suck at this topic :(

Nastasia [14]

Answer:

x is equal to 35

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The diagram below represents a relation. List the ordered pairs in the relation and tell whether or not the relation is also a f

cricket20 [7]

A relation is a set of inputs and outputs, often written as ordered pairs (input, output). We can also represent a relation as a mapping diagram or a graph. For example, the relation can be represented as:

3 0

3 years ago

[SCREENSHOT INCLUDED] If f(x) = sqrt(2x+1) then f '(4) =

Sphinxa [80]

Using the definition,

$f'(4) = \displaystyle \lim_{x\to4} \frac{f(x)-f(4)}{x-4}$

The numerator in the difference quotient is

$f(x) - f(4) = \sqrt{2x+1} - \sqrt{2\cdot4+1} = \sqrt{2x+1}-3$

Multiply the numerator and denominator by the conjugate of this expression,

$\displaystyle \frac{\sqrt{2x+1}-3}{x-4} \cdot \dfrac{\sqrt{2x+1}+3}{\sqrt{2x+1}+3}$

The modified numerator reduces to a difference of squares,

$\displaystyle \frac{\left(\sqrt{2x+1}\right)^2-3^2}{(x-4)\left(\sqrt{2x+1}+3\right)}$

Simplify this to get

$\displaystyle \frac{2x+1-9}{(x-4)\left(\sqrt{2x+1}+3\right)} = \frac{2(x-4)}{(x-4)\left(\sqrt{2x+1}+3\right)}$

Since x is approaching 4, it never actually takes on the value of 4, so (x - 4)/(x - 4) reduces to 1. Then the limit is equivalent to

$f'(4) = \displaystyle \lim_{x\to4} \frac{f(x)-f(4)}{x-4} = \lim_{x\to4}\frac2{\sqrt{2x+1}+3}$

and the remaining limand is continuous at x = 4, so that

$f'(4) = \dfrac2{\sqrt{2\cdot4+1}+3} = \dfrac26 = \boxed{\dfrac13}$

6 0

1 year ago