90 = 20 + 70.....GCF of 20 and 70 is 10
90 = 10(2 + 7) <==
can u write another expression using a different common factor...yes
90 = 20 + 70.....common factor is 5
90 = 5(4 + 14) <==
Answer:
0.4
Step-by-step explanation:
Vicki has a computer randomly select 0 or 1 three times, with 0 representing <u>heads</u> and 1 representing <u>tails</u>. The results of 15 trials are shown in the table.
110 111 000 011 000
010 101 100 000 000
111 101 110 101 111
Vicki would like to estimate the probability of tails (1) coming up fewer than 2 times (must be 0 or 1 digit 1 in record). All such seuences are marked in bold int the above table. There are 6 such trails. Hence, Vicki's estimated probability, based on this simulation is
![\dfrac{6}{15}=\dfrac{2}{5}=0.4](https://tex.z-dn.net/?f=%5Cdfrac%7B6%7D%7B15%7D%3D%5Cdfrac%7B2%7D%7B5%7D%3D0.4)
Answer:
Point T,R,P not seen how I don't understand your question.
You need to get the r by itself on one side, with the constants (numbers without the r) on the other side.