Answer:
This question lacks options, the options are:
A. All 270 tall plants were heterozygous
B. All 270 tall plants were homzygous.
C. Only 90 plants were homzygous.
D. All dwarf plants were homzygous.
The answer is D.
Explanation:
This question involves a single gene coding for height in pea plants. The allele for tallness (T) is dominant over that of dwarfness (t). This means that a dwarf plant can only be homzygous recessive (tt) while a tall plant can either be homzygous (TT) or heterozygous (Tt).
According to the question, two tall heterozygous pea plants were crossed i.e. Tt × Tt. Based on this cross, a phenotypic ratio of 3:1 is expected, which is in accordance with the 270 tall plants and 90 dwarf plants (360 total) that was obtained in the cross. Since dwarfism in pea plants is a recessive trait, this means that all the dwarf plants produced in this cross (90) were homzygous (tt).
Answer:
(D) Z
Explanation:
Cellular respiration is a catabolic process by which cells produce energy by oxidising respiratory substrates such as glucose. It is a multistage process occurs in cytoplasm and in mitochondria of a cell. The first stage of cellular respiration is called glycolysis or EMP (Embden, Meyerhof and Parnas) pathway. This stage occurs in the cytoplasm of a cell which is labeled by Z in the given image.
Answer:
The correct answer is - C. Photoautotrophs.
Explanation:
Photoautotrophs are autotrophs or organisms that are able to obtain their food by using photosynthesis. Photosynthesis is the process in which sunlight trapped by the organism and converts to inorganic material such as CO2 and H2O to organic material which is glucose or sugar molecules.
In termite's guts, various types of diverse ways of getting their nutritional needs are found according to the microbes are Chemotrophs, Heterotrophs, parasites, and decomposers.
Answer:
They can know if the trait has been carried on by looking at the bred dogs that have the trait and determining if the trait has been passed down by similar characteristics between the parent with the trait and the puppy that could have the trait.
Explanation:
