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2 years ago

5

describe and correct the error a student made finding the intercepts of the graph of the line 4x-6y=12

1 answer:

Kazeer [188]2 years ago

8 0

Answer:

sorry????

Step-by-step explanation:

mmmmmmmmm?????

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Write these ratio in its simplest form 200:180

Montano1993 [528]

Answer:

10:9

Step-by-step explanation:

4 0

2 years ago

Car is moving on a circle on a plane. At time t (seconds), its x-coordinate is given by x(t) = 10 sin(200t + 3) + 30 while its y

Aleks [24]

Answer:

we have centre of circle as (30,40) and radius = 1

Step-by-step explanation:

Given that a car is moving on a circle on a plane.

At time t (seconds),

$x(t) = 10 sin(200t + 3) + 30$

and

$y(t) = 10 cos(200t + 3) + 40$

$x-30 = 10 sin(200t + 3) \\y-40 = 10 cos(200t + 3) + 40$

when we square and add both the equations we get

$(x-30)^2 + (y-40)^2 = 1$

(since sin square + cos square = 1 always)

i.e. we have centre of circle as (30,40) and radius = 1

3 0

2 years ago

There are 2 each shape is 1 whole. what fraction greater than 1 names the parts that are shaded?

lilavasa [31]

It's three because of you have two anything bigger than two is three

6 0

2 years ago

olga nikolaevna [1]

Answer:

Fraction of the original board left = $\frac{2}{15}$

Step-by-step explanation:

Let the length of the board is = l feet

Marty saws off $\frac{1}{5}$ of a wooden board.

Length of the board left = l - $(\frac{1}{5})l$

= $(\frac{4}{5})l$ feet

He saws off $\frac{3}{4}th$ of the remaining board,

Board left = $(\frac{4}{5})l-[(\frac{4}{5})l\times (\frac{3}{4})]$

= $\frac{4}{5}l-\frac{3}{5}l$

= $\frac{1}{5}l$ feet

He finally saws off $\frac{1}{3}$ rd of the remaining board.

Board left = $\frac{1}{5}l-[\frac{1}{5}\times \frac{1}{3}]l$

= $(\frac{1}{5}-\frac{1}{15})l$

= $\frac{2}{15}l$ feet

Fraction of the original board left = $\frac{\frac{2}{15}l}{l}$

= $\frac{2}{15}$

6 0

2 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago