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nordsb [41]
3 years ago
13

s="latex-formula">
Mathematics
1 answer:
Elina [12.6K]3 years ago
5 0

Answer:

math

Step-by-step explanation:

have got a question which is as follow: Determine x,y,z∈R such that 2x2+y2+2z2−8x+2y−2xy+2xz−16z+35=0. This is a quite filthy looking equation

You might be interested in
Find tan in the triangle ​
grigory [225]

Answer:

35/12

Step-by-step explanation:

The tangent in a triangle is always the opposite side divided by the  adjacent side. In this triangle, BC is the side opposite to angle a, and AC is the side adjacent to angle A.

However, we do not know what AC is, but we can use the pythagorean theorem to solve. 37^2-35^2=144\\\\, which is 12 squared. Therefore, AC is 12 units in length.

Now we have all the sides of the triangle and we can divide the opposite side by the adjacent side. We get 35/12.

Hope this helps!

8 0
4 years ago
Find the surface area of each figure. Round to the nearest tenth if necessary.​
Lady bird [3.3K]

Answer:

Step-by-step explanation:

Base of triangle = b = 8 cm

Height of triangle = h = 6 cm

Length of rectangle = l = 6 cm

Sides of the triangle :  S1 = 6 cm ;  S2 = 8 cm and S3 = 10 cm

Surface area of triangular prism= bh + l *(s1+ S2 + S3)

                                                    = 8 * 6 + 6*(6+8+10)

                                                    = 48 + 6*24

                                                     = 48 + 144

                                                     = 192 square cm

3 0
3 years ago
Suppose F and G are continuously∗ differentiable functions defined on [a, b] such that F0(x) = G0(x) for all x ∈ [a, b]. Using t
Orlov [11]

Answer:

The proof is detailed below.

Step-by-step explanation:

We will first prove that if H(x) is a differentiable function in [a,b] such that H'(x)=0 for all x∈[a, b] then H is constant. For this, take, x,y∈[a, b] with x<y. By the Mean Value Theorem, there exists some c∈(x,y) such that H(y)-H(x)=H'(c)(x-y). But H'(c)=0, thus H(y)-H(x)=0, that is, H(x)=H(y). Then H is a constant function, as it takes the same value in any two different points x,y.

Now for this exercise, consider H(x)=F(x)-G(x). Using differentiation rules, we have that H'(x)=(F-G)(x)'=F'(x)-G'(x)=0. Applying the previous result, F-G is a constant function, that is, there exists some constant C such that (F-G)(x)=C.

3 0
4 years ago
EVALAUTE: 5|7 - 9| - 2=<br><br> a. -12<br> b. 0<br> c. 1<br> d. 8
alexandr1967 [171]
It’s d!!!!!!!!!!!!!!
3 0
4 years ago
PLZ HURRY! WILL GIVE BRAINILEST TO FIRST CORRECT ANSWER!!!!!!!!
tatuchka [14]

Answer:

2.36

Step-by-step explanation:

order of operations : pemdas

parenthesis, exponents

multiplication, division

addition, substraction

first parenthesis, so

(32-4) = 28

parenthesis again

[10+28] = 38

now you have

90/38 = 45/19 = 2.36

6 0
3 years ago
Read 2 more answers
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