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Shkiper50 [21]
3 years ago
9

I am a square number the sum of my digits is equal to 7 what square number could I be how many different numbers can you find

Mathematics
1 answer:
AleksandrR [38]3 years ago
3 0
The number is 25, it’s the only one
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Write the equation of the line for the graph shown below, please
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Answer:

Given the proposed interrogate, as well as the graph provided, the correct answer is B. Y = 1/2 x + 4

Step-by-step explanation:

To evaluate such, a comprehension of linear Cartesian planes are obligated:

Slopes = rise/run

X- intercept: The peculiar point in which linear data is observed to intersect the x-axis.

Y- intercept: The peculiar point in which linear data is observed to intersect the y-axis.

Slope: 1/2 as for every individual space endeavored, a space of 2 to the right is required.

Y- intercept: (4,0)

Thus, the ameliorated answer to such interrogate is acknowledged as B. Y = 1/2 x + 4.

*I hope this helps.

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3 years ago
1. Joshua has a ladder that is 12 ft long. He will lean the ladder against a vertical wall. For safety reasons, he wants the ang
marishachu [46]
Let h=height where top of ladder touches wall and x be distance from wall to bottom of ladder...

tana=h/x

a=arctan(h/x)  and a≤75

arctan(h/x)≤75  now taking tan of both sides :P

h/x≤tan75 now we have an ugly x value that we need to get rid of:

Using the pythagorean theorem we know:

144=x^2+h^2, x^2=144-h^2, x=√(144-h^2)  now we can use this in our inequality for x

h/√(144-h^2)≤tan75

h^2/(144-h^2)≤(tan75)^2

h^2≤144(tan75)^2-h^2(tan75)^2

h^2+h^2(tan75)^2≤144(tan75)^2

h^2(1+(tan75)^2)≤144(tan75)^2

h^2≤[144(tan75)^2]/(1+(tan75)^2)

h^2≤134.353829

h≤11.5911

So he cannot have the top of the ladder 11.8 ft above the ground and not exceed a 75° angle with the ground.

I worked it the hard way just to go through the process.  However we could have used a simple trig function to see that maximum height of the top of the ladder....

sin75=h/12

h=12sin75

h≈11.59 ft.  That would be the maximum height given that we did not want to exceed 75° with the ground.




7 0
3 years ago
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