Answer:
At least 75% of these commuting times are between 30 and 110 minutes
Step-by-step explanation:
Chebyshev Theorem
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by
.
In this question:
Mean of 70 minutes, standard deviation of 20 minutes.
Since nothing is known about the distribution, we use Chebyshev's Theorem.
What percentage of these commuting times are between 30 and 110 minutes
30 = 70 - 2*20
110 = 70 + 2*20
THis means that 30 and 110 minutes is within 2 standard deviations of the mean, which means that at least 75% of these commuting times are between 30 and 110 minutes
Answer:
C. 10 000
Step-by-step explanation:
If we called:
x = children who have been vacinated against rubella only
2x = children who have been vaccinated against mumps
y = children who have been vaccinated agains both
Children who have been vaccinated against mumps only = x - y
And we know that y = 2*(x-y)
=> 2y = 3x
y = 5000
There fore x = 7500
The number of children who have been vaccinated against rubella
= 2x - y = 2*7500 - 5000 = 15 000 - 5000 = 10 000
Between-group design compares two groups (randomly formed) on the same task, such as movement speed.
Given things that there are two groups that are randomly formed for the same task.
A between-group design in experimental design is an experiment in which two or more groups of individuals are assessed simultaneously by separate testing factors. This design is typically used instead of, or in conjunction with, the within-subject design, which applies identical modifications of circumstances to each participant in order to monitor the reactions.
Learn more about experimental designs at brainly.com/question/17280313
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Answer: i dont this you can combine like terms for this question because none of these have the same variable or anything.