let
(hypotenuse ) c = 10 in
(perpendicular) a = 8 in
(base) b =?
By using Pythagoras theorem
c^2= a^2+b^2
(10)^2 = (8)^2 +(b)^2
100 = 64 +(b)^2
100- 64 = (b)^2
36 = (b)^2
√36 = b
6 = b
hence b= 6 in
Answer: 108 degrees
============================================================
Explanation:
Angle ABC is given to be 90 degrees. By the converse of Thales Theorem, we know that AC is a diameter of the circle.
If we draw a line from A to C, it will pass through the center of the circle.
Therefore, arc AC is 180 degrees as this is half the distance around the circle.
minor arc AD = 72
minor arc CD = x
(minor arc AD) + (minor arc CD) = arc AC
72+x = 180
72+x-72 = 180-72
x = 108
minor arc CD is 108 degrees
Answer:
14/5
Step-by-step explanation:
I'd suggest rewriting both mixed numbers as improper fractions. Then we'd have:
14/3 and 5/3
Dividing 14/3 by 5/3 is equivalent to dividing 14 by 5, since the denominators are the same (3).
Quotient is 14/5.
Answer:
-11
Step-by-step explanation:
Convert -3 2/3 to -11/3
-11/3÷1/3
Dividing by 1/3 is the same as multipling by 3
so the equation becomes
(-11/3)(3)
=-11
Answer:
36 inches
Step-by-step explanation:
We know that 1 ft = 12 inches
2 ft = 2 * 12 = 24 inches
3 ft = 3*12 = 36 inches
