Answer as needed for monday pllease
1 answer:
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Check the picture below.
![\bf A=\cfrac{h(a+b)}{2}\quad \begin{cases} A=20\\ a=6z-1\\ b=2z+3\\ h=z \end{cases}\implies 20=\cfrac{z[(6z-1)~+~(2z+3)]}{2} \\\\\\ 20=\cfrac{z(8z+2)}{2}\implies 20=\cfrac{2z(4z+1)}{2}\implies 20=z(4z+1) \\\\\\ 20=4z^2+z\implies 0=4z^2+z-20](https://tex.z-dn.net/?f=%5Cbf%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D20%5C%5C%0Aa%3D6z-1%5C%5C%0Ab%3D2z%2B3%5C%5C%0Ah%3Dz%0A%5Cend%7Bcases%7D%5Cimplies%2020%3D%5Ccfrac%7Bz%5B%286z-1%29~%2B~%282z%2B3%29%5D%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0A20%3D%5Ccfrac%7Bz%288z%2B2%29%7D%7B2%7D%5Cimplies%2020%3D%5Ccfrac%7B2z%284z%2B1%29%7D%7B2%7D%5Cimplies%2020%3Dz%284z%2B1%29%0A%5C%5C%5C%5C%5C%5C%0A20%3D4z%5E2%2Bz%5Cimplies%200%3D4z%5E2%2Bz-20)
since the height is just a length unit, it can't be -2.3646.
since the height is just a length unit, it can't be -2.3646.
Answer:
One of the length of the side is 13 inches, the other length is(x=8inches)which implies that the geometry is a "rectangle not square because the length of the sides are not equal.
Step-by-step explanation:
CHECK COMPLETE QUESTION BELOW;
Maria looks at the architectural plan of a four-walled room in which the walls meet each other at right angles. The length of one wall in the plan is 13 inches. The length of the diagonal of the floor of the room in the plan is approximately 15.26 inches.
Is the room in the shape of a square? Explain how you determined your answer. Show all your work.
CHECK THE ATTACHMENT FOR FIQURE THAT GIVES THE INTERPRETATION OF THE QUESTION
Using Pythagoras rule
C² = a² + b²
Where
C= Hypotenuse side= 15.26 inches.
a= adjacent side= x
b= opposite side= 13 inches
a² = b²+ C²
= ( 15.26²- 13²)
=(232.86 - 169)= 63.87
a= √63.87= 8inches
Which means the "x" side is 8inches
One of the length of the side is 13 inches, the other length is 8inches, which implies that the geometry is a "rectangle not square because the length of the sides are not equal.
