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ki77a [65]
3 years ago
8

Is 28.42 > 28. 404 true

Mathematics
2 answers:
Tanzania [10]3 years ago
4 0

Answer:

Its true

Step-by-step explanation:28.42 has a greater value than 28.404

Sav [38]3 years ago
3 0

Answer:

28.42 > 28.404

it is true

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Jon noeds 1/3 cup of
Alex_Xolod [135]

Answer: 1 1/12

Step-by-step explanation:

1/3 + 3/4 =

1/3 x 4= 4/12

3/4 x 3 = 9/12

9/12 + 4/12 = 13/12 = 1 1/12

5 0
3 years ago
How many packages of hamburger buns and meat patties should you buy to sell at a baseball tournament?
Mandarinka [93]
13 packs of meat patties and 16 packs of buns
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4 years ago
a paint mixture contains 32 gallons of base for every gallon of color. In 924 gallons of paint, how many gallons of color are th
expeople1 [14]
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924-x/x=32/1
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8 0
4 years ago
The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

{A}' & {B}' is also independent

{A}' = 1-0.8 = 0.2

{B}' = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B')  (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

P(\frac{B'}{A}) = \frac{P(B'\cap A)}{P(A)} = \frac{0.4\times 0.8}{0.8} = 0.4

Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

=\frac{P({A}'\cap {B}')}{P({B}')} = 0.4

P({A}'\cap {B}') = 0.4 x P({B}')

= 0.4 x 0.4 = 0.16

P({A}'\cap {B}') = 0.16

i)

The probability that at least one of them is on time

P(A\cup B) = 1- P({A}'\cap {B}')  

=  1 - 0.16 = 0.84

ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0
3 years ago
Please help to solve this please with steps.
Blababa [14]

Answer:

284cm^2

Step-by-step explanation:

first, we split up the shape into seperate sections that we can easily find the areas of.

i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.

we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.

there are 2 of these, so 32 x 2 = 64cm^2.

now, i chose to seperarte the pentagon into a rectangle and a triangle,

and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.

the area of the rectangle is 150cm^2.

now, for the triangle.

the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.

8 + 7 = 15.

22 - 15 = 7.

now we know that the height of the triangle is 7 cm.

from earlier, we also know the base, which is 10cm.

7 x 10 = 70cm^2.

now we add all these together:

70 + 150 + 64 = 284cm^2

4 0
3 years ago
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