Answer:
Step-by-step explanation:
Let x represent the smaller integer.
Let y represent the larger integer.
A positive integer is 2 less than another. It means that
y = x + 2
If the sum of the reciprocal of the smaller and twice the reciprocal of the larger is 11/15, it means that
1/x + 2/y = 11/15- - - - - - - - - - 1
Substituting y = x + 2 into equation 1, it becomes
1/x + 2/(x + 2) = 11/15
Considering the left hand side of the equation, it becomes
(x + 2 + 2x)/x(x + 2)
Therefore,
(3x + 2)/(x² + 2x) = 11/15
Cross multiplying, it becomes
15(3x + 2) = 11(x² + 2x)
45x + 30 = 11x² + 22x
11x² + 22x - 45x - 30 = 0
11x² - 23x - 30 = 0
11x² + 10x - 33x - 30 = 0
x(11x + 10) - 3(11 + 10) =℅0
(x - 3)(11x + 10) = 0
x - 3 = 0 or 11x + 10 = 0
x = 3 or x = - 10/11
Since it us a positive integer, the smaller integer is 3 and the larger integer is 3 + 2 = 5
