The first pump empties half the pond in 3 hours, so in 1/6 that time (1/2 hour), it empties (1/6)·(1/2) = 1/12 of the pond.
The second pump empties the other 5/12 of the pond in that half hour, so has a pumping rate of (1/2 h)/(5/12 pond) = (6/5 h)/pond.
The second pump could do the entire job alone in 1 hour and 12 minutes.
(3t² +t -12t - 4)(t+2)=0
(3t³ - 5t² -26t -8) =0
t = -2
Answer:
17
Step-by-step explanation:
D = 8.5 miles/h x 2h
= 17 miles
