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MissTica
3 years ago
12

What is the measure in radians for the central angle of a circle whose radius is 6 cm and intercept arc length is 5. 4 cm?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
Ok, so find circumference
arc/circumferece=xrad/2pirad


c=2pir
c=2pi6
c=12pi
arc=5.4cm

5.4/12pi=x/2pi
tims both sides by 2pi
5.4/6=x
0.9=x
0.9 radians
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Which value of www makes 14=11+\dfrac{w}{8}\cdot614=11+ 8 w ​ ⋅614, equals, 11, plus, start fraction, w, divided by, 8, end frac
Liono4ka [1.6K]

Answer:

Option B) w = 4

Step-by-step explanation:

We have to find the value of w to make the given expression true.

The given expression is:

14=11+\dfrac{w}{8}\cdot6\\\\14-11 = \dfrac{w}{8}\cdot6\\\\3 = \dfrac{w}{8}\cdot6\\\\\Rightarrow w = \dfrac{3 \cdot 8}{6} = 4

Option B) w = 4 is the correct answer.

8 0
3 years ago
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Solve<br> 15x +4&lt; 26.5<br> Need help fast pls
d1i1m1o1n [39]

Answer:

x<1.5

explanation: move 4 to other side subtract it with 26.5 then divide it by 15

5 0
3 years ago
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In tossing four fair dice, what is the probability of tossing, at most, one 3
11Alexandr11 [23.1K]

<u>Answer- </u>

In tossing four fair dice, the probability of getting at most one 3 is 0.86.

<u>Solution-</u>

The probability of getting at most one 3 is, either getting zero 3 or only one 3.

P(A) =The \ probability \ of \ getting \ zero \ 3 =(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6})=\frac{625}{1296} =0.48                    ( ∵ xxxx )

P(B) = The \ probability \ of \ getting \ only \ one \ 3 =(4)(\frac{1}{6})(\frac{5}{6})(\frac{5}{6})(\frac{5}{6}) = 0.38                    ( ∵ 3xxx, x3xx, xx3x, xxx3 )

P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86

7 0
3 years ago
I HAVE LIKE 2 MORE QUESTIONS, HELP ME PLZ!
Ne4ueva [31]

Given:

Base length of triangle = 10 units

Height of triangle = \sqrt{44} units

Length of hypotenuse of triangle = 12 units

To find:

Exact value of Cos A

Steps:

The cosine of any angle is equal to the length of the adjacent side by the length of the hypotenuse side.

So,

Cos A = \frac{adjacent}{hypotenuse}

Cos A = \frac{10}{12}

Cos A = 0.833

Therefore, the exact value of cos A is 0.833.

Happy to help :)

If u need any help, feel free to ask

5 0
3 years ago
Home CoworkHelper
9966 [12]

Answer:

See below.

Step-by-step explanation:

PROBLEM A

The formula for the volume of a cylinder is

V = πr²h, where πr² is the area of the base.

V = area of base x height

  1. Choose any four numbers that are less than 10 for the height.
  2. Then, substitute into the formula and isolate "r". 10 = πr²h
  3. Double "r" to find the diameter.
  4. The area of the base is found (bolded) while you solve πr².

*I will use the calculator button for pi (π)

<u>Cylinder A: </u><u>h = 1</u>

10 = πr²h

10 = πr²(1)

10 = πr²                       Area of the base is 10m².

r = √ (10/π)

r = 1.78                        Radius is 1.78m.

d = 2r = 1.78*2 = 3.56                     Diameter is 3.56m.

<u>Cylinder B: </u><u>h = 2</u>

10 = πr²h

10 = πr²(2)

5 = πr²                       Area of the base is 5m².

r = √ (5/π)

r = 1.26                      Radius is 1.26m.

d = 2r = 1.26*2 = 2.52                     Diameter is 2.52m.

<u>Cylinder C: </u><u>h = 4</u>

10 = πr²h

10 = πr²(4)

2.5 = πr²                       Area of the base is 2.5m².

r = √ (2.5/π)

r = 0.89                        Radius is 0.89m.

d = 2r = 0.89*2 = 1.78                     Diameter is 1.78m.

<u>Cylinder D: </u><u>h = 5</u>

10 = πr²h

10 = πr²(5)

2 = πr²                       Area of the base is 2m².

r = √ (2/π)

r = 0.80                     Radius is 0.8m.

d = 2r = 0.80*2 = 1.6                     Diameter is 1.6m.

The answers are reasonable if the answer is close to 10 when you substitute the rounded numbers back into the formula and solve.

There are infinite possibilities because any numbers when used in the formula equates to 10 are possible. The height/radius can be any decimal number, which would make the other dimensions change.

PROBLEM B

Follow similar steps if you know the diameter of a cylinder. Use the same formula V = πr²h.

We need the radius, which is half the diameter. r = d/2 = 10/2 = 5

  1. Choose a random number for volume that divides easily by 25.
  2. Substitute "V" and "r²" (r² = 25).
  3. Isolate "h".
  4. The area of the base is 78.54 cm² every time (A = πr²).

<u>Cylinder A: </u><u>V = 100</u>

100 = π25h

4 = πh

h = 1.27                      The height is 1.27m.

<u>Cylinder B: </u><u>V = 200</u>

200 = π25h

8 = πh

h = 2.55                      The height is 2.55m.

<u>Cylinder C: </u><u>V = 75</u>

75 = π25h

3 = πh

h = 0.95                      The height is 0.95m.

<u>Cylinder D: </u><u>V = 125</u>

125 = π25h

5 = πh

h = 1.59                      The height is 1.59m.

The answers are reasonable if I can substitute two rounded values into the formula and get a number close to the third. The height is also a decimal number which occurs because of pi.

6 0
3 years ago
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