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notsponge [240]
3 years ago
8

How does the mass of the earth comapre to the mass of the moon?​

Geography
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Explanation:

The moon's mass is 7.35 x 1022 kg, about 1.2 percent of Earth's mass. Put another way, Earth weighs 81 times more than the moon. The moon's density is 3.34 grams per cubic centimeter (3.34 g/cm3).

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In nuclear fission and fusion reactions mass is converted into energy. The average person in US uses around 100,000,000 J of ene
daser333 [38]

Answer:

a) The yearly energy consumption for a US population of 300 million is 3\times 10^{16} J/year

b) The energy that would be released if a 60 kg person were converted entirely into energy is 5.4\times 10^{18} Joules.

c) 180 years would this amount of energy support a population of 300 million.

Explanation:

a) Average energy consumed by single person of US = 100,000,000 J/year

Then 300 million US citizen will consume:

300 million = 300 × 1,000,000 = 3\times 10^8

The yearly energy consumption for a US population :

100,000,000 J/year\times 3\times 10^8=3\times 10^{16} J/year

The yearly energy consumption for a US population of 300 million is 3\times 10^{16} J/year

b) E = m\times c^2

E = Energy from converted mass of m

c = speed of light

Given mass of person = m = 60 kg

E=60 kg\times (3\times 10^8 m/s)^2 = 5.4\times 10^{18} J

c) Energy calculated in part (b) = E=5.4\times 10^{18} J

The yearly energy consumption for a US population  of 300 million in an year = 3\times 10^{16} J/year

Let the that would be supported by 5.4\times 10^{18} Joules of energy be x.

x\times 3\times 10^{16} J/year=5.4\times 10^{18} J

x=\frac{5.4\times 10^{18} J}{3\times 10^{16} J/year}=180 years

180 years would this amount of energy support a population of 300 million.

4 0
3 years ago
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