The midsegment is half the length of the base.
1) 32 ÷ 2 = 16
<em>So</em><em>,</em><em> 16 is the midsegment</em>
2) 11 ÷ 2 = 5.5
<em>So, 5.5 is the midsegment</em>
3) 32 ÷ 2 = 16
<em>So</em><em>,</em><em> 16 is the midsegment</em>
<em>4</em><em>)</em><em> </em>14 ÷ 2 = 7
<em>S</em><em>o</em><em>,</em><em> </em><em>7</em><em> </em><em>i</em><em>s</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>i</em><em>d</em><em>s</em><em>e</em><em>g</em><em>m</em><em>e</em><em>n</em><em>t</em>
See below for the domain and the range of the functions.
<h3>How to determine the domain and the range?</h3>
As a general rule, all linear functions have a domain and a range of all set of real numbers i.e. (−∞, ∞)
The functions (2), (3), (4), (5) and (6) are linear functions.
So, their domain and range are (−∞,∞)
For function (1), we have:
f(x) = 3(3)^x - 1
The above is an exponential function.
The domain of an exponential function is all set of real numbers i.e. (−∞, ∞)
Read more about domain and range at:
brainly.com/question/1632425
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Find area of the base
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6 x 6 = 36cm²
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Find the area of one triangle
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1/2 x 6 x 8 = 24 cm²
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Find the area of 4 triangles
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24 x 4 = 96cm²
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Total Surface Area
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96 + 36 = 132cm²
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Answer: 132 cm²
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Answer:
f(5) = 26.672 which is option D
Step-by-step explanation:
From question, f(1) = 2 and f'(x)=√(x^3 + 6)
f(5) = f(1) + (5,1)∫ f'(x) dx
Integrating using the boundary 5 and 1;
f(5) = 2 + (5,1)∫√(x^3 + 6) dx
f(5) = 2 + 24.672
So f(5) = 26.672
