$44.80 I could be wrong let me know
Each van carries 13 students and each bus carries 25 students.
<h3><u>Distribution</u></h3>
Given that the senior class at High School A and the senior class at High School B both planned trips to Yellowstone, and the senior class at High School A rented and filled 5 vans and 2 buses with 115 students, while High School B rented and filled 1 van and 6 buses with 163 students, and each van carried the same number of students and each bus carried the same number of students, to determine the number of students in each van and in each bus, the following calculation must be made:
- 5X + 2Y = 115
- 1X + 6Y = 163
- 5X + 2Y = 115
- 5X + 30Y = 815
- 815 - 115 = 28Y
- 700 = 28Y
- Y = 700 / 28
- y = 25
- 1X + 6x25 = 163
- 1X = 163 - 150
- X = 13
Therefore, each van carries 13 students and each bus carries 25 students.
Learn more about distribution in brainly.com/question/14310262
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5x+14-2x=9-(4x+2)
3x+14=9-4x-2
3x+14=7-4x
7x+14=7
7x=-7
x=-1
Final answer: x=-1
<h2>Answer: </h2>
We know that,
Length of arc = 2 × 3.14 × 6 × 45/360
Length of arc = 6.28 × 3/4
= 18.84/4
= 4.71units.
Answer:
y = 38 + 72t - 16t^2
Step-by-step explanation:
So, solve for t when y=48.
The max height is of course, when t = 64/32 = 2.
