Answer:
Therefore r'(t) =-k sin t i + k cos t j and |r'(t)| = k so T(t) = r'(t)/|r'(t)| = -sin t i + cos t j and T'(t) = -cos t i- sin t j . This gives |T'(t)| = 1, so using this equation, we have κ(t) = |T'(t)|/|r'(t)| = 1/k.
Step-by-step explanation:
We are already given the definition of curvature and the parametrization needed to find the curvature of the circle. In genecral the curvature κ is equal to κ(t)=|T'(t)|/|r'(t)| where r(t) is a parametrization of the curve and T(t) is the normalized tangent vector respect to the parametrization, that is, T(t)=r'(t)/|r'(t)|.
Now, using the derivatives of sines and cosines, and the definition of norm, we obtain that:
r(t) = k cos t i + k sin t j ⇒ r'(t)=-k sin t i + k cos t j ⇒|r'(t)|²=sin²t+cos²t=1
T(t) = r'(t)/|r'(t)|=-sin t i +cos t j ⇒ T'(t)= -cos t i - sin t j ⇒|T'(t)|²=cos²t+sin²t=1
C. 40
30x30=900
40x40=1600
total of 2500 take the square root and your left with 50 so everything balances out
First you can solve for angle C because angles C and D are vertical and therefore congruent
So we do: 62+44+x=180 and solve
106+x=180
x=74
So then we know that angles C and D are 74 degrees
Then we can solve for angle F:
x+74+50=180
Which can be rewritten as x=180-50-74
Hope this helps
Answer:
C. The rudely disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the politely disagrees condition has a mean of 3.82 and standard deviation of 0.97
Step-by-step explanation:
The given data is
x` Std. Dev
R. disagrees 4.16 0.854
P. disagrees 3.82 0.967
From this data we see that the R. disagrees has a mean of 4.16 and standard deviation of 0.854
while
the P. disagrees has a mean of 3.82 and standard deviation of 0.967.
Same figures are given only in option C because
Rounding 0.854 gives 0.85
Rounding 0.967 gives 0.97
So only option C is the best choice.
C. The R. Disagrees condition has a mean of 4.16 and a standard deviation of 0.85 while the P. Disagrees condition has a mean of 3.82 and standard deviation of 0.97
